Precalculus Examples

$\frac{\ln (1.1702)}{0.078}$

Step 1

Replace $e$ with an approximation.

$\frac{\log_{2.71828182} (1.1702)}{0.078}$

Step 2

Log base $2.71828182$ of $1.1702$ is approximately $0.15717467$ .

$\frac{0.15717467}{0.078}$

Step 3

Divide $0.15717467$ by $0.078$ .

$2.01505992$