Precalculus Examples

$\frac{\ln (0.6)}{8.92 \cdot 10^{- 10}}$

Step 1

Simplify the expression.

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Step 1.1

Move $10^{- 10}$ to the numerator using the negative exponent rule $\frac{1}{b^{- n}} = b^{n}$ .

$\frac{\ln (0.6) \cdot 10^{10}}{8.92}$

Step 1.2

Raise $10$ to the power of $10$ .

$\frac{\ln (0.6) \cdot 10000000000}{8.92}$

Step 2

Simplify the numerator.

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Step 2.1

Reorder $\ln (0.6)$ and $10000000000$ .

$\frac{10000000000 \cdot \ln (0.6)}{8.92}$

Step 2.2

Simplify $10000000000 \cdot \ln (0.6)$ by moving $10000000000$ inside the logarithm.

$\frac{\ln ({0.6}^{10000000000})}{8.92}$

Step 3

Replace $e$ with an approximation.

$\frac{\log_{2.71828182} ({0.6}^{10000000000})}{8.92}$

Step 4

Expand $\log_{2.71828182} ({0.6}^{10000000000})$ by moving $10000000000$ outside the logarithm.

$\frac{10000000000 \log_{2.71828182} (0.6)}{8.92}$

Step 5

Log base $2.71828182$ of $0.6$ is approximately $- 0.51082562$ .

$\frac{10000000000 \cdot - 0.51082562}{8.92}$

Step 6

Multiply $10000000000$ by $- 0.51082562$ .

$\frac{- 5108256237.65992}{8.92}$

Step 7

Divide $- 5108256237.65992$ by $8.92$ .

$- 572674466.10537219$