Precalculus Examples

$\frac{\ln (\frac{19}{28})}{\ln (2)} \cdot - 1600$

Step 1

Multiply $\frac{\ln (\frac{19}{28})}{\ln (2)} \cdot - 1600$ .

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Step 1.1

Combine $\frac{\ln (\frac{19}{28})}{\ln (2)}$ and $- 1600$ .

$\frac{\ln (\frac{19}{28}) \cdot - 1600}{\ln (2)}$

Step 1.2

Reorder $\ln (\frac{19}{28})$ and $- 1600$ .

$\frac{- 1600 \cdot \ln (\frac{19}{28})}{\ln (2)}$

Step 1.3

Simplify $- 1600 \cdot \ln (\frac{19}{28})$ by moving $1600$ inside the logarithm.

$\frac{- \ln ({(\frac{19}{28})}^{1600})}{\ln (2)}$

Step 2

Apply the product rule to $\frac{19}{28}$ .

$\frac{- \ln (\frac{19^{1600}}{28^{1600}})}{\ln (2)}$

Step 3

Move the negative in front of the fraction.

$- \frac{\ln (\frac{19^{1600}}{28^{1600}})}{\ln (2)}$