Precalculus Examples

$\frac{\log (16.5)}{\log (0.4)}$

Step 1

Log base $10$ of $16.5$ is approximately $1.21748394$ .

$\frac{1.21748394}{\log (0.4)}$

Step 2

Log base $10$ of $0.4$ is approximately $- 0.39794$ .

$\frac{1.21748394}{- 0.39794}$

Step 3

Divide $1.21748394$ by $- 0.39794$ .

$- 3.05946604$