Precalculus Examples

$\frac{\log (13.7)}{\log (0.7)}$

Step 1

Log base $10$ of $13.7$ is approximately $1.13672056$ .

$\frac{1.13672056}{\log (0.7)}$

Step 2

Log base $10$ of $0.7$ is approximately $- 0.15490195$ .

$\frac{1.13672056}{- 0.15490195}$

Step 3

Divide $1.13672056$ by $- 0.15490195$ .

$- 7.33832268$