Precalculus Examples

$\frac{\log (2)}{\log (1.06)}$

Step 1

Log base $10$ of $1.06$ is approximately $0.02530586$ .

$\frac{\log (2)}{0.02530586}$

Step 2

Log base $10$ of $2$ is approximately $0.30102999$ .

$\frac{0.30102999}{0.02530586}$

Step 3

Divide $0.30102999$ by $0.02530586$ .

$11.89566104$