Precalculus Examples

$\frac{\log (3) \log (8)}{\log (1.6) + \log (8)}$

Step 1

Log base $10$ of $1.6$ is approximately $0.20411998$ .

$\frac{\log (3) \log (8)}{0.20411998 + \log (8)}$

Step 2

Add $0.20411998$ and $\log (8)$ .

$\frac{\log (3) \log (8)}{1.10720996}$

Step 3

Log base $10$ of $3$ is approximately $0.47712125$ .

$\frac{0.47712125 \log (8)}{1.10720996}$

Step 4

Log base $10$ of $8$ is approximately $0.90308998$ .

$\frac{0.47712125 \cdot 0.90308998}{1.10720996}$

Step 5

Multiply $0.47712125$ by $0.90308998$ .

$\frac{0.43088342}{1.10720996}$

Step 6

Divide $0.43088342$ by $1.10720996$ .

$0.38916144$