Precalculus Examples

$(- 12, 7)$ , $y - i n t = - 15$ , $x - i n t = 5$

Step 1

Remove parentheses.

$7 - i n t = - 15$

$(- 12) - i n t = 5$

Step 2

Move all terms not containing $n$ to the right side of the equation.

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Step 2.1

Subtract $7$ from both sides of the equation.

$- i n t = - 15 - 7$

$(- 12) - i n t = 5$

Step 2.2

Subtract $7$ from $- 15$ .

$- i n t = - 22$

$(- 12) - i n t = 5$

$- i n t = - 22$

$(- 12) - i n t = 5$

Step 3

Divide each term in $- i n t = - 22$ by $- i t$ and simplify.

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Step 3.1

Divide each term in $- i n t = - 22$ by $- i t$ .

$\frac{- i n t}{- i t} = \frac{- 22}{- i t}$

$(- 12) - i n t = 5$

Step 3.2

Simplify the left side.

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Step 3.2.1

Dividing two negative values results in a positive value.

$\frac{i n t}{i t} = \frac{- 22}{- i t}$

$(- 12) - i n t = 5$

Step 3.2.2

Cancel the common factor of $i$ .

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Step 3.2.2.1

Cancel the common factor.

$\frac{i n t}{i t} = \frac{- 22}{- i t}$

$(- 12) - i n t = 5$

Step 3.2.2.2

Rewrite the expression.

$\frac{n t}{t} = \frac{- 22}{- i t}$

$(- 12) - i n t = 5$

$\frac{n t}{t} = \frac{- 22}{- i t}$

$(- 12) - i n t = 5$

Step 3.2.3

Cancel the common factor of $t$ .

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Step 3.2.3.1

Cancel the common factor.

$\frac{n t}{t} = \frac{- 22}{- i t}$

$(- 12) - i n t = 5$

Step 3.2.3.2

Divide $n$ by $1$ .

$n = \frac{- 22}{- i t}$

$(- 12) - i n t = 5$

$n = \frac{- 22}{- i t}$

$(- 12) - i n t = 5$

$n = \frac{- 22}{- i t}$

$(- 12) - i n t = 5$

Step 3.3

Simplify the right side.

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Step 3.3.1

Dividing two negative values results in a positive value.

$n = \frac{22}{i t}$

$(- 12) - i n t = 5$

$n = \frac{22}{i t}$

$(- 12) - i n t = 5$

$n = \frac{22}{i t}$

$(- 12) - i n t = 5$

Step 4

Remove parentheses.

$- 12 - i n t = 5$

$n = \frac{22}{i t}$

Step 5

Move all terms not containing $n$ to the right side of the equation.

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Step 5.1

Add $12$ to both sides of the equation.

$- i n t = 5 + 12$

$n = \frac{22}{i t}$

Step 5.2

Add $5$ and $12$ .

$- i n t = 17$

$n = \frac{22}{i t}$

$- i n t = 17$

$n = \frac{22}{i t}$

Step 6

Divide each term in $- i n t = 17$ by $- i t$ and simplify.

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Step 6.1

Divide each term in $- i n t = 17$ by $- i t$ .

$\frac{- i n t}{- i t} = \frac{17}{- i t}$

$n = \frac{22}{i t}$

Step 6.2

Simplify the left side.

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Step 6.2.1

Dividing two negative values results in a positive value.

$\frac{i n t}{i t} = \frac{17}{- i t}$

$n = \frac{22}{i t}$

Step 6.2.2

Cancel the common factor of $i$ .

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Step 6.2.2.1

Cancel the common factor.

$\frac{i n t}{i t} = \frac{17}{- i t}$

$n = \frac{22}{i t}$

Step 6.2.2.2

Rewrite the expression.

$\frac{n t}{t} = \frac{17}{- i t}$

$n = \frac{22}{i t}$

$\frac{n t}{t} = \frac{17}{- i t}$

$n = \frac{22}{i t}$

Step 6.2.3

Cancel the common factor of $t$ .

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Step 6.2.3.1

Cancel the common factor.

$\frac{n t}{t} = \frac{17}{- i t}$

$n = \frac{22}{i t}$

Step 6.2.3.2

Divide $n$ by $1$ .

$n = \frac{17}{- i t}$

$n = \frac{22}{i t}$

$n = \frac{17}{- i t}$

$n = \frac{22}{i t}$

$n = \frac{17}{- i t}$

$n = \frac{22}{i t}$

Step 6.3

Simplify the right side.

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Step 6.3.1

Move the negative in front of the fraction.

$n = - \frac{17}{i t}$

$n = \frac{22}{i t}$

$n = - \frac{17}{i t}$

$n = \frac{22}{i t}$

$n = - \frac{17}{i t}$

$n = \frac{22}{i t}$

Step 7

The ordered pair is a solution to the system of equations.

$(- 12, 7)$ is a solution