Precalculus Examples

$x + 2 + y^{2} = 20$ , $(- 4, 2)$

Step 1

Insert the values of $x = - 4$ and $y = 2$ into the equation to find if the ordered pair is a solution.

$(- 4) + 2 + {(2)}^{2} = 20$

Step 2

Simplify $(- 4) + 2 + {(2)}^{2}$ .

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Step 2.1

Raise $2$ to the power of $2$ .

$(- 4) + 2 + 4 = 20$

Step 2.2

Add $- 4$ and $2$ .

$- 2 + 4 = 20$

Step 2.3

Add $- 2$ and $4$ .

$2 = 20$

Step 3

Since $2 \neq 20$ , there are no solutions.

No solution

Step 4

Since the equation is not true when the values are used, the ordered pair is not a solution.

The ordered pair is not a solution to the equation.