Precalculus Examples

$4 x - k y = 6$ , $6 x + 3 y + 2 = 0$

Step 1

Solve the equation for $x$ .

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Step 1.1

Add $k y$ to both sides of the equation.

$4 x = 6 + k y$

$6 x + 3 y + 2 = 0$

Step 1.2

Divide each term in $4 x = 6 + k y$ by $4$ and simplify.

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Step 1.2.1

Divide each term in $4 x = 6 + k y$ by $4$ .

$\frac{4 x}{4} = \frac{6}{4} + \frac{k y}{4}$

$6 x + 3 y + 2 = 0$

Step 1.2.2

Simplify the left side.

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Step 1.2.2.1

Cancel the common factor of $4$ .

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Step 1.2.2.1.1

Cancel the common factor.

$\frac{4 x}{4} = \frac{6}{4} + \frac{k y}{4}$

$6 x + 3 y + 2 = 0$

Step 1.2.2.1.2

Divide $x$ by $1$ .

$x = \frac{6}{4} + \frac{k y}{4}$

$6 x + 3 y + 2 = 0$

$x = \frac{6}{4} + \frac{k y}{4}$

$6 x + 3 y + 2 = 0$

$x = \frac{6}{4} + \frac{k y}{4}$

$6 x + 3 y + 2 = 0$

Step 1.2.3

Simplify the right side.

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Step 1.2.3.1

Cancel the common factor of $6$ and $4$ .

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Step 1.2.3.1.1

Factor $2$ out of $6$ .

$x = \frac{2 (3)}{4} + \frac{k y}{4}$

$6 x + 3 y + 2 = 0$

Step 1.2.3.1.2

Cancel the common factors.

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Step 1.2.3.1.2.1

Factor $2$ out of $4$ .

$x = \frac{2 \cdot 3}{2 \cdot 2} + \frac{k y}{4}$

$6 x + 3 y + 2 = 0$

Step 1.2.3.1.2.2

Cancel the common factor.

$x = \frac{2 \cdot 3}{2 \cdot 2} + \frac{k y}{4}$

$6 x + 3 y + 2 = 0$

Step 1.2.3.1.2.3

Rewrite the expression.

$x = \frac{3}{2} + \frac{k y}{4}$

$6 x + 3 y + 2 = 0$

$x = \frac{3}{2} + \frac{k y}{4}$

$6 x + 3 y + 2 = 0$

$x = \frac{3}{2} + \frac{k y}{4}$

$6 x + 3 y + 2 = 0$

$x = \frac{3}{2} + \frac{k y}{4}$

$6 x + 3 y + 2 = 0$

$x = \frac{3}{2} + \frac{k y}{4}$

$6 x + 3 y + 2 = 0$

$x = \frac{3}{2} + \frac{k y}{4}$

$6 x + 3 y + 2 = 0$

Step 2

Solve the equation for $y$ .

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Step 2.1

Simplify $6 (\frac{3}{2} + \frac{k y}{4}) + 3 y + 2$ .

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Step 2.1.1

Simplify each term.

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Step 2.1.1.1

Apply the distributive property.

$6 (\frac{3}{2}) + 6 (\frac{k y}{4}) + 3 y + 2 = 0$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.1.1.2

Cancel the common factor of $2$ .

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Step 2.1.1.2.1

Factor $2$ out of $6$ .

$2 (3) (\frac{3}{2}) + 6 (\frac{k y}{4}) + 3 y + 2 = 0$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.1.1.2.2

Cancel the common factor.

$2 \cdot (3 (\frac{3}{2})) + 6 (\frac{k y}{4}) + 3 y + 2 = 0$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.1.1.2.3

Rewrite the expression.

$3 \cdot 3 + 6 (\frac{k y}{4}) + 3 y + 2 = 0$

$x = \frac{3}{2} + \frac{k y}{4}$

$3 \cdot 3 + 6 (\frac{k y}{4}) + 3 y + 2 = 0$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.1.1.3

Multiply $3$ by $3$ .

$9 + 6 (\frac{k y}{4}) + 3 y + 2 = 0$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.1.1.4

Cancel the common factor of $2$ .

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Step 2.1.1.4.1

Factor $2$ out of $6$ .

$9 + 2 (3) (\frac{k y}{4}) + 3 y + 2 = 0$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.1.1.4.2

Factor $2$ out of $4$ .

$9 + 2 \cdot (3 (\frac{k y}{2 \cdot 2})) + 3 y + 2 = 0$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.1.1.4.3

Cancel the common factor.

$9 + 2 \cdot (3 (\frac{k y}{2 \cdot 2})) + 3 y + 2 = 0$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.1.1.4.4

Rewrite the expression.

$9 + 3 (\frac{k y}{2}) + 3 y + 2 = 0$

$x = \frac{3}{2} + \frac{k y}{4}$

$9 + 3 (\frac{k y}{2}) + 3 y + 2 = 0$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.1.1.5

Combine $3$ and $\frac{k y}{2}$ .

$9 + \frac{3 k y}{2} + 3 y + 2 = 0$

$x = \frac{3}{2} + \frac{k y}{4}$

$9 + \frac{3 k y}{2} + 3 y + 2 = 0$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.1.2

Add $9$ and $2$ .

$\frac{3 k y}{2} + 3 y + 11 = 0$

$x = \frac{3}{2} + \frac{k y}{4}$

$\frac{3 k y}{2} + 3 y + 11 = 0$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.2

Subtract $11$ from both sides of the equation.

$\frac{3 k y}{2} + 3 y = - 11$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.3

Factor $3 y$ out of $\frac{3 k y}{2} + 3 y$ .

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Step 2.3.1

Factor $3 y$ out of $\frac{3 k y}{2}$ .

$3 y (\frac{k}{2}) + 3 y = - 11$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.3.2

Factor $3 y$ out of $3 y$ .

$3 y (\frac{k}{2}) + 3 y (1) = - 11$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.3.3

Factor $3 y$ out of $3 y \frac{k}{2} + 3 y (1)$ .

$3 y (\frac{k}{2} + 1) = - 11$

$x = \frac{3}{2} + \frac{k y}{4}$

$3 y (\frac{k}{2} + 1) = - 11$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.4

Divide each term in $3 y (\frac{k}{2} + 1) = - 11$ by $3 (\frac{k}{2} + 1)$ and simplify.

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Step 2.4.1

Divide each term in $3 y (\frac{k}{2} + 1) = - 11$ by $3 (\frac{k}{2} + 1)$ .

$\frac{3 y (\frac{k}{2} + 1)}{3 (\frac{k}{2} + 1)} = \frac{- 11}{3 (\frac{k}{2} + 1)}$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.4.2

Simplify the left side.

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Step 2.4.2.1

Cancel the common factor of $3$ .

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Step 2.4.2.1.1

Cancel the common factor.

$\frac{3 y (\frac{k}{2} + 1)}{3 (\frac{k}{2} + 1)} = \frac{- 11}{3 (\frac{k}{2} + 1)}$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.4.2.1.2

Rewrite the expression.

$\frac{y (\frac{k}{2} + 1)}{\frac{k}{2} + 1} = \frac{- 11}{3 (\frac{k}{2} + 1)}$

$x = \frac{3}{2} + \frac{k y}{4}$

$\frac{y (\frac{k}{2} + 1)}{\frac{k}{2} + 1} = \frac{- 11}{3 (\frac{k}{2} + 1)}$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.4.2.2

Cancel the common factor of $\frac{k}{2} + 1$ .

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Step 2.4.2.2.1

Cancel the common factor.

$\frac{y (\frac{k}{2} + 1)}{\frac{k}{2} + 1} = \frac{- 11}{3 (\frac{k}{2} + 1)}$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.4.2.2.2

Divide $y$ by $1$ .

$y = \frac{- 11}{3 (\frac{k}{2} + 1)}$

$x = \frac{3}{2} + \frac{k y}{4}$

$y = \frac{- 11}{3 (\frac{k}{2} + 1)}$

$x = \frac{3}{2} + \frac{k y}{4}$

$y = \frac{- 11}{3 (\frac{k}{2} + 1)}$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.4.3

Simplify the right side.

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Step 2.4.3.1

Simplify the denominator.

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Step 2.4.3.1.1

Write $1$ as a fraction with a common denominator.

$y = \frac{- 11}{3 (\frac{k}{2} + \frac{2}{2})}$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.4.3.1.2

Combine the numerators over the common denominator.

$y = \frac{- 11}{3 (\frac{k + 2}{2})}$

$x = \frac{3}{2} + \frac{k y}{4}$

$y = \frac{- 11}{3 (\frac{k + 2}{2})}$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.4.3.2

Combine $3$ and $\frac{k + 2}{2}$ .

$y = \frac{- 11}{\frac{3 (k + 2)}{2}}$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.4.3.3

Multiply the numerator by the reciprocal of the denominator.

$y = - 11 \frac{2}{3 (k + 2)}$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.4.3.4

Multiply $- 11 \frac{2}{3 (k + 2)}$ .

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Step 2.4.3.4.1

Combine $- 11$ and $\frac{2}{3 (k + 2)}$ .

$y = \frac{- 11 \cdot 2}{3 (k + 2)}$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.4.3.4.2

Multiply $- 11$ by $2$ .

$y = \frac{- 22}{3 (k + 2)}$

$x = \frac{3}{2} + \frac{k y}{4}$

$y = \frac{- 22}{3 (k + 2)}$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 2.4.3.5

Move the negative in front of the fraction.

$y = - \frac{22}{3 (k + 2)}$

$x = \frac{3}{2} + \frac{k y}{4}$

$y = - \frac{22}{3 (k + 2)}$

$x = \frac{3}{2} + \frac{k y}{4}$

$y = - \frac{22}{3 (k + 2)}$

$x = \frac{3}{2} + \frac{k y}{4}$

$y = - \frac{22}{3 (k + 2)}$

$x = \frac{3}{2} + \frac{k y}{4}$

Step 3

Simplify the right side.

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Step 3.1

Simplify each term.

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Step 3.1.1

Combine $k$ and $\frac{22}{3 (k + 2)}$ .

$x = \frac{3}{2} + \frac{- \frac{k \cdot 22}{3 (k + 2)}}{4}$

$y = - \frac{22}{3 (k + 2)}$

Step 3.1.2

Move $22$ to the left of $k$ .

$x = \frac{3}{2} + \frac{- \frac{22 k}{3 (k + 2)}}{4}$

$y = - \frac{22}{3 (k + 2)}$

Step 3.1.3

Multiply the numerator by the reciprocal of the denominator.

$x = \frac{3}{2} - \frac{22 k}{3 (k + 2)} \cdot \frac{1}{4}$

$y = - \frac{22}{3 (k + 2)}$

Step 3.1.4

Cancel the common factor of $2$ .

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Step 3.1.4.1

Move the leading negative in $- \frac{22 k}{3 (k + 2)}$ into the numerator.

$x = \frac{3}{2} + \frac{- 22 k}{3 (k + 2)} \cdot \frac{1}{4}$

$y = - \frac{22}{3 (k + 2)}$

Step 3.1.4.2

Factor $2$ out of $- 22 k$ .

$x = \frac{3}{2} + \frac{2 (- 11 k)}{3 (k + 2)} \cdot \frac{1}{4}$

$y = - \frac{22}{3 (k + 2)}$

Step 3.1.4.3

Factor $2$ out of $4$ .

$x = \frac{3}{2} + \frac{2 (- 11 k)}{3 (k + 2)} \cdot \frac{1}{2 (2)}$

$y = - \frac{22}{3 (k + 2)}$

Step 3.1.4.4

Cancel the common factor.

$x = \frac{3}{2} + \frac{2 (- 11 k)}{3 (k + 2)} \cdot \frac{1}{2 \cdot 2}$

$y = - \frac{22}{3 (k + 2)}$

Step 3.1.4.5

Rewrite the expression.

$x = \frac{3}{2} + \frac{- 11 k}{3 (k + 2)} \cdot \frac{1}{2}$

$y = - \frac{22}{3 (k + 2)}$

$x = \frac{3}{2} + \frac{- 11 k}{3 (k + 2)} \cdot \frac{1}{2}$

$y = - \frac{22}{3 (k + 2)}$

Step 3.1.5

Multiply $\frac{- 11 k}{3 (k + 2)}$ by $\frac{1}{2}$ .

$x = \frac{3}{2} + \frac{- 11 k}{3 (k + 2) \cdot 2}$

$y = - \frac{22}{3 (k + 2)}$

Step 3.1.6

Multiply $2$ by $3$ .

$x = \frac{3}{2} + \frac{- 11 k}{6 (k + 2)}$

$y = - \frac{22}{3 (k + 2)}$

Step 3.1.7

Move the negative in front of the fraction.

$x = \frac{3}{2} - \frac{11 k}{6 (k + 2)}$

$y = - \frac{22}{3 (k + 2)}$

$x = \frac{3}{2} - \frac{11 k}{6 (k + 2)}$

$y = - \frac{22}{3 (k + 2)}$

$x = \frac{3}{2} - \frac{11 k}{6 (k + 2)}$

$y = - \frac{22}{3 (k + 2)}$