Precalculus Examples

$3 x - 3 y - k z = 3 k$ , $x - y = 3$ , $2 x + 2 y + 4 = 6$

Step 1

Solve the equation for $x$ .

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Step 1.1

Move all terms not containing $x$ to the right side of the equation.

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Step 1.1.1

Add $3 y$ to both sides of the equation.

$3 x - k z = 3 k + 3 y$

$x - y = 3$

$2 x + 2 y + 4 = 6$

Step 1.1.2

Add $k z$ to both sides of the equation.

$3 x = 3 k + 3 y + k z$

$x - y = 3$

$2 x + 2 y + 4 = 6$

$3 x = 3 k + 3 y + k z$

$x - y = 3$

$2 x + 2 y + 4 = 6$

Step 1.2

Divide each term in $3 x = 3 k + 3 y + k z$ by $3$ and simplify.

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Step 1.2.1

Divide each term in $3 x = 3 k + 3 y + k z$ by $3$ .

$\frac{3 x}{3} = \frac{3 k}{3} + \frac{3 y}{3} + \frac{k z}{3}$

$x - y = 3$

$2 x + 2 y + 4 = 6$

Step 1.2.2

Simplify the left side.

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Step 1.2.2.1

Cancel the common factor of $3$ .

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Step 1.2.2.1.1

Cancel the common factor.

$\frac{3 x}{3} = \frac{3 k}{3} + \frac{3 y}{3} + \frac{k z}{3}$

$x - y = 3$

$2 x + 2 y + 4 = 6$

Step 1.2.2.1.2

Divide $x$ by $1$ .

$x = \frac{3 k}{3} + \frac{3 y}{3} + \frac{k z}{3}$

$x - y = 3$

$2 x + 2 y + 4 = 6$

$x = \frac{3 k}{3} + \frac{3 y}{3} + \frac{k z}{3}$

$x - y = 3$

$2 x + 2 y + 4 = 6$

$x = \frac{3 k}{3} + \frac{3 y}{3} + \frac{k z}{3}$

$x - y = 3$

$2 x + 2 y + 4 = 6$

Step 1.2.3

Simplify the right side.

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Step 1.2.3.1

Simplify each term.

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Step 1.2.3.1.1

Cancel the common factor of $3$ .

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Step 1.2.3.1.1.1

Cancel the common factor.

$x = \frac{3 k}{3} + \frac{3 y}{3} + \frac{k z}{3}$

$x - y = 3$

$2 x + 2 y + 4 = 6$

Step 1.2.3.1.1.2

Divide $k$ by $1$ .

$x = k + \frac{3 y}{3} + \frac{k z}{3}$

$x - y = 3$

$2 x + 2 y + 4 = 6$

$x = k + \frac{3 y}{3} + \frac{k z}{3}$

$x - y = 3$

$2 x + 2 y + 4 = 6$

Step 1.2.3.1.2

Cancel the common factor of $3$ .

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Step 1.2.3.1.2.1

Cancel the common factor.

$x = k + \frac{3 y}{3} + \frac{k z}{3}$

$x - y = 3$

$2 x + 2 y + 4 = 6$

Step 1.2.3.1.2.2

Divide $y$ by $1$ .

$x = k + y + \frac{k z}{3}$

$x - y = 3$

$2 x + 2 y + 4 = 6$

$x = k + y + \frac{k z}{3}$

$x - y = 3$

$2 x + 2 y + 4 = 6$

$x = k + y + \frac{k z}{3}$

$x - y = 3$

$2 x + 2 y + 4 = 6$

$x = k + y + \frac{k z}{3}$

$x - y = 3$

$2 x + 2 y + 4 = 6$

$x = k + y + \frac{k z}{3}$

$x - y = 3$

$2 x + 2 y + 4 = 6$

$x = k + y + \frac{k z}{3}$

$x - y = 3$

$2 x + 2 y + 4 = 6$

Step 2

Solve the equation for $y$ .

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Step 2.1

Combine the opposite terms in $(k + y + \frac{k z}{3}) - y$ .

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Step 2.1.1

Subtract $y$ from $y$ .

$k + \frac{k z}{3} + 0 = 3$

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

Step 2.1.2

Add $k + \frac{k z}{3}$ and $0$ .

$k + \frac{k z}{3} = 3$

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

$k + \frac{k z}{3} = 3$

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

Step 2.2

Factor $k$ out of $k + \frac{k z}{3}$ .

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Step 2.2.1

Factor $k$ out of $k^{1}$ .

$k \cdot 1 + \frac{k z}{3} = 3$

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

Step 2.2.2

Factor $k$ out of $\frac{k z}{3}$ .

$k \cdot 1 + k (\frac{z}{3}) = 3$

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

Step 2.2.3

Factor $k$ out of $k \cdot 1 + k \frac{z}{3}$ .

$k \cdot (1 + \frac{z}{3}) = 3$

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

Step 2.2.4

Multiply $k$ by $1 + \frac{z}{3}$ .

$k (1 + \frac{z}{3}) = 3$

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

$k (1 + \frac{z}{3}) = 3$

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

Step 2.3

Divide each term in $k (1 + \frac{z}{3}) = 3$ by $1 + \frac{z}{3}$ and simplify.

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Step 2.3.1

Divide each term in $k (1 + \frac{z}{3}) = 3$ by $1 + \frac{z}{3}$ .

$\frac{k (1 + \frac{z}{3})}{1 + \frac{z}{3}} = \frac{3}{1 + \frac{z}{3}}$

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

Step 2.3.2

Simplify the left side.

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Step 2.3.2.1

Cancel the common factor of $1 + \frac{z}{3}$ .

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Step 2.3.2.1.1

Cancel the common factor.

$\frac{k (1 + \frac{z}{3})}{1 + \frac{z}{3}} = \frac{3}{1 + \frac{z}{3}}$

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

Step 2.3.2.1.2

Divide $k$ by $1$ .

$k = \frac{3}{1 + \frac{z}{3}}$

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

$k = \frac{3}{1 + \frac{z}{3}}$

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

$k = \frac{3}{1 + \frac{z}{3}}$

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

Step 2.3.3

Simplify the right side.

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Step 2.3.3.1

Simplify the denominator.

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Step 2.3.3.1.1

Write $1$ as a fraction with a common denominator.

$k = \frac{3}{\frac{3}{3} + \frac{z}{3}}$

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

Step 2.3.3.1.2

Combine the numerators over the common denominator.

$k = \frac{3}{\frac{3 + z}{3}}$

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

$k = \frac{3}{\frac{3 + z}{3}}$

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

Step 2.3.3.2

Multiply the numerator by the reciprocal of the denominator.

$k = 3 (\frac{3}{3 + z})$

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

Step 2.3.3.3

Multiply $3 \frac{3}{3 + z}$ .

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Step 2.3.3.3.1

Combine $3$ and $\frac{3}{3 + z}$ .

$k = \frac{3 \cdot 3}{3 + z}$

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

Step 2.3.3.3.2

Multiply $3$ by $3$ .

$k = \frac{9}{3 + z}$

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

$k = \frac{9}{3 + z}$

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

$k = \frac{9}{3 + z}$

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

$k = \frac{9}{3 + z}$

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

Step 2.4

The variable $y$ got canceled.

All real numbers

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

All real numbers

$x = k + y + \frac{k z}{3}$

$2 x + 2 y + 4 = 6$

Step 3

Solve the equation for $z$ .

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Step 3.1

Simplify $3 (k + A l \cdot l (r e a l) (n u m b e r s) + \frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z$ .

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Step 3.1.1

Simplify each term.

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Step 3.1.1.1

Simplify each term.

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Step 3.1.1.1.1

Multiply $l$ by $l$ by adding the exponents.

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Step 3.1.1.1.1.1

Move $l$ .

$3 (k + A (l \cdot l) (r e a l) (n u m b e r s) + \frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.1.1.2

Multiply $l$ by $l$ .

$3 (k + A l^{2} (r e a l) (n u m b e r s) + \frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

$3 (k + A l^{2} (r e a l) (n u m b e r s) + \frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.1.2

Multiply $l^{2}$ by $l$ by adding the exponents.

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Step 3.1.1.1.2.1

Move $l$ .

$3 (k + A (l \cdot l^{2}) (r e a) (n u m b e r s) + \frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.1.2.2

Multiply $l$ by $l^{2}$ .

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Step 3.1.1.1.2.2.1

Raise $l$ to the power of $1$ .

$3 (k + A (l \cdot l^{2}) (r e a) (n u m b e r s) + \frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.1.2.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$3 (k + A l^{1 + 2} (r e a) (n u m b e r s) + \frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

$3 (k + A l^{1 + 2} (r e a) (n u m b e r s) + \frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.1.2.3

Add $1$ and $2$ .

$3 (k + A l^{3} (r e a) (n u m b e r s) + \frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

$3 (k + A l^{3} (r e a) (n u m b e r s) + \frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.1.3

Multiply $r$ by $r$ by adding the exponents.

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Step 3.1.1.1.3.1

Move $r$ .

$3 (k + A l^{3} (r \cdot r e a) (n u m b e s) + \frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.1.3.2

Multiply $r$ by $r$ .

$3 (k + A l^{3} (r^{2} e a) (n u m b e s) + \frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

$3 (k + A l^{3} (r^{2} e a) (n u m b e s) + \frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.1.4

Rewrite using the commutative property of multiplication.

$3 (k + e A l^{3} r^{2} a (n u m b e s) + \frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.1.5

Multiply $e A l^{3} r^{2} a (n u m b e s)$ .

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Step 3.1.1.1.5.1

Raise $e$ to the power of $1$ .

$3 (k + A l^{3} r^{2} a (n u m b (e e) s) + \frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.1.5.2

Raise $e$ to the power of $1$ .

$3 (k + A l^{3} r^{2} a (n u m b (e e) s) + \frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.1.5.3

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$3 (k + A l^{3} r^{2} a (n u m b e^{1 + 1} s) + \frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.1.5.4

Add $1$ and $1$ .

$3 (k + A l^{3} r^{2} a (n u m b e^{2} s) + \frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

$3 (k + A l^{3} r^{2} a (n u m b e^{2} s) + \frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.1.6

Rewrite using the commutative property of multiplication.

$3 (k + e^{2} A l^{3} r^{2} a n u m b s + \frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

$3 (k + e^{2} A l^{3} r^{2} a n u m b s + \frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.2

Apply the distributive property.

$3 k + 3 (e^{2} A l^{3} r^{2} a n u m b s) + 3 (\frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.3

Cancel the common factor of $3$ .

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Step 3.1.1.3.1

Cancel the common factor.

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + 3 (\frac{k z}{3}) - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.3.2

Rewrite the expression.

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 (A l \cdot l (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.4

Multiply $l$ by $l$ by adding the exponents.

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Step 3.1.1.4.1

Move $l$ .

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 (A (l \cdot l) (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.4.2

Multiply $l$ by $l$ .

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 (A l^{2} (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 (A l^{2} (r e a l) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.5

Multiply $l^{2}$ by $l$ by adding the exponents.

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Step 3.1.1.5.1

Move $l$ .

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 (A (l \cdot l^{2}) (r e a) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.5.2

Multiply $l$ by $l^{2}$ .

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Step 3.1.1.5.2.1

Raise $l$ to the power of $1$ .

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 (A (l \cdot l^{2}) (r e a) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.5.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 (A l^{1 + 2} (r e a) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 (A l^{1 + 2} (r e a) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.5.3

Add $1$ and $2$ .

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 (A l^{3} (r e a) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 (A l^{3} (r e a) (n u m b e r s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.6

Multiply $r$ by $r$ by adding the exponents.

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Step 3.1.1.6.1

Move $r$ .

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 (A l^{3} (r \cdot r e a) (n u m b e s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.6.2

Multiply $r$ by $r$ .

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 (A l^{3} (r^{2} e a) (n u m b e s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 (A l^{3} (r^{2} e a) (n u m b e s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.7

Rewrite using the commutative property of multiplication.

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 (e A l^{3} r^{2} a (n u m b e s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.8

Multiply $e A l^{3} r^{2} a (n u m b e s)$ .

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Step 3.1.1.8.1

Raise $e$ to the power of $1$ .

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 (A l^{3} r^{2} a (n u m b (e e) s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.8.2

Raise $e$ to the power of $1$ .

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 (A l^{3} r^{2} a (n u m b (e e) s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.8.3

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 (A l^{3} r^{2} a (n u m b e^{1 + 1} s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.8.4

Add $1$ and $1$ .

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 (A l^{3} r^{2} a (n u m b e^{2} s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 (A l^{3} r^{2} a (n u m b e^{2} s)) - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.1.9

Rewrite using the commutative property of multiplication.

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 e^{2} A l^{3} r^{2} a n u m b s - k z = 3 k$

$2 x + 2 y + 4 = 6$

$3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 e^{2} A l^{3} r^{2} a n u m b s - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.2

Combine the opposite terms in $3 k + 3 e^{2} A l^{3} r^{2} a n u m b s + k z - 3 e^{2} A l^{3} r^{2} a n u m b s - k z$ .

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Step 3.1.2.1

Subtract $3 e^{2} A l^{3} r^{2} a n u m b s$ from $3 e^{2} A l^{3} r^{2} a n u m b s$ .

$3 k + k z + 0 - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.2.2

Add $3 k + k z$ and $0$ .

$3 k + k z - k z = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.2.3

Subtract $k z$ from $k z$ .

$3 k + 0 = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.1.2.4

Add $3 k$ and $0$ .

$3 k = 3 k$

$2 x + 2 y + 4 = 6$

$3 k = 3 k$

$2 x + 2 y + 4 = 6$

$3 k = 3 k$

$2 x + 2 y + 4 = 6$

Step 3.2

Divide each term in $3 k = 3 k$ by $3$ and simplify.

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Step 3.2.1

Divide each term in $3 k = 3 k$ by $3$ .

$\frac{3 k}{3} = \frac{3 k}{3}$

$2 x + 2 y + 4 = 6$

Step 3.2.2

Simplify the left side.

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Step 3.2.2.1

Cancel the common factor of $3$ .

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Step 3.2.2.1.1

Cancel the common factor.

$\frac{3 k}{3} = \frac{3 k}{3}$

$2 x + 2 y + 4 = 6$

Step 3.2.2.1.2

Divide $k$ by $1$ .

$k = \frac{3 k}{3}$

$2 x + 2 y + 4 = 6$

$k = \frac{3 k}{3}$

$2 x + 2 y + 4 = 6$

$k = \frac{3 k}{3}$

$2 x + 2 y + 4 = 6$

Step 3.2.3

Simplify the right side.

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Step 3.2.3.1

Cancel the common factor of $3$ .

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Step 3.2.3.1.1

Cancel the common factor.

$k = \frac{3 k}{3}$

$2 x + 2 y + 4 = 6$

Step 3.2.3.1.2

Divide $k$ by $1$ .

$k = k$

$2 x + 2 y + 4 = 6$

$k = k$

$2 x + 2 y + 4 = 6$

$k = k$

$2 x + 2 y + 4 = 6$

$k = k$

$2 x + 2 y + 4 = 6$

Step 3.3

The variable $z$ got canceled.

All real numbers

$2 x + 2 y + 4 = 6$

All real numbers

$2 x + 2 y + 4 = 6$