Precalculus Examples

$4 x - 3 y + z = 18$ , $x + y = 7$

Step 1

Solve the equation for $x$ .

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Step 1.1

Move all terms not containing $x$ to the right side of the equation.

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Step 1.1.1

Add $3 y$ to both sides of the equation.

$4 x + z = 18 + 3 y$

$x + y = 7$

Step 1.1.2

Subtract $z$ from both sides of the equation.

$4 x = 18 + 3 y - z$

$x + y = 7$

$4 x = 18 + 3 y - z$

$x + y = 7$

Step 1.2

Divide each term in $4 x = 18 + 3 y - z$ by $4$ and simplify.

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Step 1.2.1

Divide each term in $4 x = 18 + 3 y - z$ by $4$ .

$\frac{4 x}{4} = \frac{18}{4} + \frac{3 y}{4} + \frac{- z}{4}$

$x + y = 7$

Step 1.2.2

Simplify the left side.

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Step 1.2.2.1

Cancel the common factor of $4$ .

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Step 1.2.2.1.1

Cancel the common factor.

$\frac{4 x}{4} = \frac{18}{4} + \frac{3 y}{4} + \frac{- z}{4}$

$x + y = 7$

Step 1.2.2.1.2

Divide $x$ by $1$ .

$x = \frac{18}{4} + \frac{3 y}{4} + \frac{- z}{4}$

$x + y = 7$

$x = \frac{18}{4} + \frac{3 y}{4} + \frac{- z}{4}$

$x + y = 7$

$x = \frac{18}{4} + \frac{3 y}{4} + \frac{- z}{4}$

$x + y = 7$

Step 1.2.3

Simplify the right side.

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Step 1.2.3.1

Simplify each term.

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Step 1.2.3.1.1

Cancel the common factor of $18$ and $4$ .

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Step 1.2.3.1.1.1

Factor $2$ out of $18$ .

$x = \frac{2 (9)}{4} + \frac{3 y}{4} + \frac{- z}{4}$

$x + y = 7$

Step 1.2.3.1.1.2

Cancel the common factors.

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Step 1.2.3.1.1.2.1

Factor $2$ out of $4$ .

$x = \frac{2 \cdot 9}{2 \cdot 2} + \frac{3 y}{4} + \frac{- z}{4}$

$x + y = 7$

Step 1.2.3.1.1.2.2

Cancel the common factor.

$x = \frac{2 \cdot 9}{2 \cdot 2} + \frac{3 y}{4} + \frac{- z}{4}$

$x + y = 7$

Step 1.2.3.1.1.2.3

Rewrite the expression.

$x = \frac{9}{2} + \frac{3 y}{4} + \frac{- z}{4}$

$x + y = 7$

$x = \frac{9}{2} + \frac{3 y}{4} + \frac{- z}{4}$

$x + y = 7$

$x = \frac{9}{2} + \frac{3 y}{4} + \frac{- z}{4}$

$x + y = 7$

Step 1.2.3.1.2

Move the negative in front of the fraction.

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

$x + y = 7$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

$x + y = 7$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

$x + y = 7$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

$x + y = 7$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

$x + y = 7$

Step 2

Solve the equation for $y$ .

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Step 2.1

Simplify $(\frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}) + y$ .

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Step 2.1.1

To write $y$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$\frac{9}{2} - \frac{z}{4} + \frac{3 y}{4} + y \cdot \frac{4}{4} = 7$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 2.1.2

Simplify terms.

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Step 2.1.2.1

Combine $y$ and $\frac{4}{4}$ .

$\frac{9}{2} - \frac{z}{4} + \frac{3 y}{4} + \frac{y \cdot 4}{4} = 7$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 2.1.2.2

Combine the numerators over the common denominator.

$\frac{9}{2} - \frac{z}{4} + \frac{3 y + y \cdot 4}{4} = 7$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 2.1.2.3

Combine the numerators over the common denominator.

$\frac{9}{2} + \frac{- z + 3 y + y \cdot 4}{4} = 7$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

$\frac{9}{2} + \frac{- z + 3 y + y \cdot 4}{4} = 7$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 2.1.3

Move $4$ to the left of $y$ .

$\frac{9}{2} + \frac{- z + 3 y + 4 y}{4} = 7$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 2.1.4

Add $3 y$ and $4 y$ .

$\frac{9}{2} + \frac{- z + 7 y}{4} = 7$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 2.1.5

To write $\frac{9}{2}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{9}{2} \cdot \frac{2}{2} + \frac{- z + 7 y}{4} = 7$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 2.1.6

Write each expression with a common denominator of $4$ , by multiplying each by an appropriate factor of $1$ .

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Step 2.1.6.1

Multiply $\frac{9}{2}$ by $\frac{2}{2}$ .

$\frac{9 \cdot 2}{2 \cdot 2} + \frac{- z + 7 y}{4} = 7$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 2.1.6.2

Multiply $2$ by $2$ .

$\frac{9 \cdot 2}{4} + \frac{- z + 7 y}{4} = 7$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

$\frac{9 \cdot 2}{4} + \frac{- z + 7 y}{4} = 7$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 2.1.7

Combine the numerators over the common denominator.

$\frac{9 \cdot 2 - z + 7 y}{4} = 7$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 2.1.8

Multiply $9$ by $2$ .

$\frac{18 - z + 7 y}{4} = 7$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

$\frac{18 - z + 7 y}{4} = 7$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 2.2

Multiply both sides by $4$ .

$\frac{18 - z + 7 y}{4} \cdot 4 = 7 \cdot 4$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 2.3

Simplify.

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Step 2.3.1

Simplify the left side.

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Step 2.3.1.1

Simplify $\frac{18 - z + 7 y}{4} \cdot 4$ .

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Step 2.3.1.1.1

Cancel the common factor of $4$ .

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Step 2.3.1.1.1.1

Cancel the common factor.

$\frac{18 - z + 7 y}{4} \cdot 4 = 7 \cdot 4$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 2.3.1.1.1.2

Rewrite the expression.

$18 - z + 7 y = 7 \cdot 4$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

$18 - z + 7 y = 7 \cdot 4$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 2.3.1.1.2

Simplify the expression.

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Step 2.3.1.1.2.1

Move $18$ .

$- z + 7 y + 18 = 7 \cdot 4$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 2.3.1.1.2.2

Reorder $- z$ and $7 y$ .

$7 y - z + 18 = 7 \cdot 4$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

$7 y - z + 18 = 7 \cdot 4$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

$7 y - z + 18 = 7 \cdot 4$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

$7 y - z + 18 = 7 \cdot 4$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 2.3.2

Simplify the right side.

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Step 2.3.2.1

Multiply $7$ by $4$ .

$7 y - z + 18 = 28$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

$7 y - z + 18 = 28$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

$7 y - z + 18 = 28$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 2.4

Solve for $y$ .

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Step 2.4.1

Move all terms not containing $y$ to the right side of the equation.

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Step 2.4.1.1

Add $z$ to both sides of the equation.

$7 y + 18 = 28 + z$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 2.4.1.2

Subtract $18$ from both sides of the equation.

$7 y = 28 + z - 18$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 2.4.1.3

Subtract $18$ from $28$ .

$7 y = z + 10$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

$7 y = z + 10$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 2.4.2

Divide each term in $7 y = z + 10$ by $7$ and simplify.

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Step 2.4.2.1

Divide each term in $7 y = z + 10$ by $7$ .

$\frac{7 y}{7} = \frac{z}{7} + \frac{10}{7}$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 2.4.2.2

Simplify the left side.

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Step 2.4.2.2.1

Cancel the common factor of $7$ .

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Step 2.4.2.2.1.1

Cancel the common factor.

$\frac{7 y}{7} = \frac{z}{7} + \frac{10}{7}$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 2.4.2.2.1.2

Divide $y$ by $1$ .

$y = \frac{z}{7} + \frac{10}{7}$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

$x = \frac{9}{2} + \frac{3 y}{4} - \frac{z}{4}$

Step 3

Simplify the right side.

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Step 3.1

Simplify $\frac{9}{2} + \frac{3 (\frac{z}{7} + \frac{10}{7})}{4} - \frac{z}{4}$ .

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Step 3.1.1

Combine the numerators over the common denominator.

$x = \frac{9}{2} + \frac{3 (\frac{z}{7} + \frac{10}{7}) - z}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.2

Simplify each term.

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Step 3.1.2.1

Apply the distributive property.

$x = \frac{9}{2} + \frac{3 (\frac{z}{7}) + 3 (\frac{10}{7}) - z}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.2.2

Combine $3$ and $\frac{z}{7}$ .

$x = \frac{9}{2} + \frac{\frac{3 z}{7} + 3 (\frac{10}{7}) - z}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.2.3

Multiply $3 (\frac{10}{7})$ .

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Step 3.1.2.3.1

Combine $3$ and $\frac{10}{7}$ .

$x = \frac{9}{2} + \frac{\frac{3 z}{7} + \frac{3 \cdot 10}{7} - z}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.2.3.2

Multiply $3$ by $10$ .

$x = \frac{9}{2} + \frac{\frac{3 z}{7} + \frac{30}{7} - z}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

$x = \frac{9}{2} + \frac{\frac{3 z}{7} + \frac{30}{7} - z}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

$x = \frac{9}{2} + \frac{\frac{3 z}{7} + \frac{30}{7} - z}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.3

To write $- z$ as a fraction with a common denominator, multiply by $\frac{7}{7}$ .

$x = \frac{9}{2} + \frac{\frac{3 z}{7} - z \cdot \frac{7}{7} + \frac{30}{7}}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.4

Simplify terms.

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Step 3.1.4.1

Combine $- z$ and $\frac{7}{7}$ .

$x = \frac{9}{2} + \frac{\frac{3 z}{7} + \frac{- z \cdot 7}{7} + \frac{30}{7}}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.4.2

Combine the numerators over the common denominator.

$x = \frac{9}{2} + \frac{\frac{3 z - z \cdot 7}{7} + \frac{30}{7}}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.4.3

Combine the numerators over the common denominator.

$x = \frac{9}{2} + \frac{\frac{3 z - z \cdot 7 + 30}{7}}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.4.4

Multiply $7$ by $- 1$ .

$x = \frac{9}{2} + \frac{\frac{3 z - 7 z + 30}{7}}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.4.5

Subtract $7 z$ from $3 z$ .

$x = \frac{9}{2} + \frac{\frac{- 4 z + 30}{7}}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.4.6

Factor $2$ out of $- 4 z + 30$ .

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Step 3.1.4.6.1

Factor $2$ out of $- 4 z$ .

$x = \frac{9}{2} + \frac{\frac{2 (- 2 z) + 30}{7}}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.4.6.2

Factor $2$ out of $30$ .

$x = \frac{9}{2} + \frac{\frac{2 (- 2 z) + 2 (15)}{7}}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.4.6.3

Factor $2$ out of $2 (- 2 z) + 2 (15)$ .

$x = \frac{9}{2} + \frac{\frac{2 (- 2 z + 15)}{7}}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

$x = \frac{9}{2} + \frac{\frac{2 (- 2 z + 15)}{7}}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.4.7

Factor $- 1$ out of $- 2 z$ .

$x = \frac{9}{2} + \frac{\frac{2 (- (2 z) + 15)}{7}}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.4.8

Rewrite $15$ as $- 1 (- 15)$ .

$x = \frac{9}{2} + \frac{\frac{2 (- (2 z) - 1 \cdot - 15)}{7}}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.4.9

Factor $- 1$ out of $- (2 z) - 1 (- 15)$ .

$x = \frac{9}{2} + \frac{\frac{2 (- (2 z - 15))}{7}}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.4.10

Simplify the expression.

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Step 3.1.4.10.1

Rewrite $- (2 z - 15)$ as $- 1 (2 z - 15)$ .

$x = \frac{9}{2} + \frac{\frac{2 (- 1 (2 z - 15))}{7}}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.4.10.2

Move the negative in front of the fraction.

$x = \frac{9}{2} + \frac{- \frac{2 (2 z - 15)}{7}}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

$x = \frac{9}{2} + \frac{- \frac{2 (2 z - 15)}{7}}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

$x = \frac{9}{2} + \frac{- \frac{2 (2 z - 15)}{7}}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.5

Simplify each term.

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Step 3.1.5.1

Multiply the numerator by the reciprocal of the denominator.

$x = \frac{9}{2} - \frac{2 (2 z - 15)}{7} \cdot \frac{1}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.5.2

Cancel the common factor of $2$ .

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Step 3.1.5.2.1

Move the leading negative in $- \frac{2 (2 z - 15)}{7}$ into the numerator.

$x = \frac{9}{2} + \frac{- 2 (2 z - 15)}{7} \cdot \frac{1}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.5.2.2

Factor $2$ out of $- 2 (2 z - 15)$ .

$x = \frac{9}{2} + \frac{2 (- (2 z - 15))}{7} \cdot \frac{1}{4}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.5.2.3

Factor $2$ out of $4$ .

$x = \frac{9}{2} + \frac{2 (- (2 z - 15))}{7} \cdot \frac{1}{2 (2)}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.5.2.4

Cancel the common factor.

$x = \frac{9}{2} + \frac{2 (- (2 z - 15))}{7} \cdot \frac{1}{2 \cdot 2}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.5.2.5

Rewrite the expression.

$x = \frac{9}{2} + \frac{- (2 z - 15)}{7} \cdot \frac{1}{2}$

$y = \frac{z}{7} + \frac{10}{7}$

$x = \frac{9}{2} + \frac{- (2 z - 15)}{7} \cdot \frac{1}{2}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.5.3

Multiply $\frac{- (2 z - 15)}{7}$ by $\frac{1}{2}$ .

$x = \frac{9}{2} + \frac{- (2 z - 15)}{7 \cdot 2}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.5.4

Multiply $7$ by $2$ .

$x = \frac{9}{2} + \frac{- (2 z - 15)}{14}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.5.5

Move the negative in front of the fraction.

$x = \frac{9}{2} - \frac{2 z - 15}{14}$

$y = \frac{z}{7} + \frac{10}{7}$

$x = \frac{9}{2} - \frac{2 z - 15}{14}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.6

To write $\frac{9}{2}$ as a fraction with a common denominator, multiply by $\frac{7}{7}$ .

$x = \frac{9}{2} \cdot \frac{7}{7} - \frac{2 z - 15}{14}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.7

Write each expression with a common denominator of $14$ , by multiplying each by an appropriate factor of $1$ .

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Step 3.1.7.1

Multiply $\frac{9}{2}$ by $\frac{7}{7}$ .

$x = \frac{9 \cdot 7}{2 \cdot 7} - \frac{2 z - 15}{14}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.7.2

Multiply $2$ by $7$ .

$x = \frac{9 \cdot 7}{14} - \frac{2 z - 15}{14}$

$y = \frac{z}{7} + \frac{10}{7}$

$x = \frac{9 \cdot 7}{14} - \frac{2 z - 15}{14}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.8

Combine the numerators over the common denominator.

$x = \frac{9 \cdot 7 - (2 z - 15)}{14}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.9

Simplify the numerator.

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Step 3.1.9.1

Multiply $9$ by $7$ .

$x = \frac{63 - (2 z - 15)}{14}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.9.2

Apply the distributive property.

$x = \frac{63 - (2 z) + 15}{14}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.9.3

Multiply $2$ by $- 1$ .

$x = \frac{63 - 2 z + 15}{14}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.9.4

Multiply $- 1$ by $- 15$ .

$x = \frac{63 - 2 z + 15}{14}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.9.5

Add $63$ and $15$ .

$x = \frac{- 2 z + 78}{14}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.9.6

Factor $2$ out of $- 2 z + 78$ .

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Step 3.1.9.6.1

Factor $2$ out of $- 2 z$ .

$x = \frac{2 (- z) + 78}{14}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.9.6.2

Factor $2$ out of $78$ .

$x = \frac{2 (- z) + 2 (39)}{14}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.9.6.3

Factor $2$ out of $2 (- z) + 2 (39)$ .

$x = \frac{2 (- z + 39)}{14}$

$y = \frac{z}{7} + \frac{10}{7}$

$x = \frac{2 (- z + 39)}{14}$

$y = \frac{z}{7} + \frac{10}{7}$

$x = \frac{2 (- z + 39)}{14}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.10

Cancel the common factors.

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Step 3.1.10.1

Factor $2$ out of $14$ .

$x = \frac{2 (- z + 39)}{2 \cdot 7}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.10.2

Cancel the common factor.

$x = \frac{2 (- z + 39)}{2 \cdot 7}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.10.3

Rewrite the expression.

$x = \frac{- z + 39}{7}$

$y = \frac{z}{7} + \frac{10}{7}$

$x = \frac{- z + 39}{7}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.11

Factor $- 1$ out of $- z$ .

$x = \frac{- (z) + 39}{7}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.12

Rewrite $39$ as $- 1 (- 39)$ .

$x = \frac{- (z) - 1 \cdot - 39}{7}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.13

Factor $- 1$ out of $- (z) - 1 (- 39)$ .

$x = \frac{- (z - 39)}{7}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.14

Simplify the expression.

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Step 3.1.14.1

Rewrite $- (z - 39)$ as $- 1 (z - 39)$ .

$x = \frac{- 1 (z - 39)}{7}$

$y = \frac{z}{7} + \frac{10}{7}$

Step 3.1.14.2

Move the negative in front of the fraction.

$x = - \frac{z - 39}{7}$

$y = \frac{z}{7} + \frac{10}{7}$

$x = - \frac{z - 39}{7}$

$y = \frac{z}{7} + \frac{10}{7}$

$x = - \frac{z - 39}{7}$

$y = \frac{z}{7} + \frac{10}{7}$

$x = - \frac{z - 39}{7}$

$y = \frac{z}{7} + \frac{10}{7}$