Precalculus Examples

$a x + b y + 2 c z = 25$ , $a x - b y - c z = 0$

Step 1

Solve the equation for $x$ .

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Move all terms not containing $x$ to the right side of the equation.

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Subtract $b y$ from both sides of the equation.

$a x + 2 c z = 25 - b y$

$a x - b y - c z = 0$

Subtract $2 c z$ from both sides of the equation.

$a x = 25 - b y - 2 c z$

$a x - b y - c z = 0$

$a x = 25 - b y - 2 c z$

$a x - b y - c z = 0$

Divide each term in $a x = 25 - b y - 2 c z$ by $a$ and simplify.

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Divide each term in $a x = 25 - b y - 2 c z$ by $a$ .

$\frac{a x}{a} = \frac{25}{a} + \frac{- b y}{a} + \frac{- 2 c z}{a}$

$a x - b y - c z = 0$

Simplify the left side.

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Cancel the common factor of $a$ .

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Cancel the common factor.

$\frac{a x}{a} = \frac{25}{a} + \frac{- b y}{a} + \frac{- 2 c z}{a}$

$a x - b y - c z = 0$

Divide $x$ by $1$ .

$x = \frac{25}{a} + \frac{- b y}{a} + \frac{- 2 c z}{a}$

$a x - b y - c z = 0$

$x = \frac{25}{a} + \frac{- b y}{a} + \frac{- 2 c z}{a}$

$a x - b y - c z = 0$

$x = \frac{25}{a} + \frac{- b y}{a} + \frac{- 2 c z}{a}$

$a x - b y - c z = 0$

Simplify the right side.

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Simplify each term.

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Move the negative in front of the fraction.

$x = \frac{25}{a} - \frac{b y}{a} + \frac{- 2 c z}{a}$

$a x - b y - c z = 0$

Move the negative in front of the fraction.

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

$a x - b y - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

$a x - b y - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

$a x - b y - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

$a x - b y - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

$a x - b y - c z = 0$

Step 2

Solve the equation for $b$ .

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Simplify $a (\frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}) - b y - c z$ .

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Simplify each term.

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Apply the distributive property.

$a (\frac{25}{a}) + a (- \frac{b y}{a}) + a (- \frac{2 c z}{a}) - b y - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Simplify.

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Cancel the common factor of $a$ .

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Cancel the common factor.

$a (\frac{25}{a}) + a (- \frac{b y}{a}) + a (- \frac{2 c z}{a}) - b y - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Rewrite the expression.

$25 + a (- \frac{b y}{a}) + a (- \frac{2 c z}{a}) - b y - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

$25 + a (- \frac{b y}{a}) + a (- \frac{2 c z}{a}) - b y - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Rewrite using the commutative property of multiplication.

$25 - a \frac{b y}{a} + a (- \frac{2 c z}{a}) - b y - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Rewrite using the commutative property of multiplication.

$25 - a \frac{b y}{a} - a \frac{2 c z}{a} - b y - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

$25 - a \frac{b y}{a} - a \frac{2 c z}{a} - b y - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Simplify each term.

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Cancel the common factor of $a$ .

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Factor $a$ out of $- a$ .

$25 + a \cdot (- 1 \frac{b y}{a}) - a \frac{2 c z}{a} - b y - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Cancel the common factor.

$25 + a \cdot (- 1 \frac{b y}{a}) - a \frac{2 c z}{a} - b y - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Rewrite the expression.

$25 - (b y) - a \frac{2 c z}{a} - b y - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

$25 - (b y) - a \frac{2 c z}{a} - b y - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Cancel the common factor of $a$ .

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Factor $a$ out of $- a$ .

$25 - b y + a \cdot (- 1 \frac{2 c z}{a}) - b y - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Cancel the common factor.

$25 - b y + a \cdot (- 1 \frac{2 c z}{a}) - b y - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Rewrite the expression.

$25 - b y - (2 c z) - b y - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

$25 - b y - (2 c z) - b y - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Multiply $2$ by $- 1$ .

$25 - b y - 2 c z - b y - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

$25 - b y - 2 c z - b y - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

$25 - b y - 2 c z - b y - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Simplify by adding terms.

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Subtract $b y$ from $- b y$ .

$25 - 2 b y - 2 c z - c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Subtract $c z$ from $- 2 c z$ .

$25 - 2 b y - 3 c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

$25 - 2 b y - 3 c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

$25 - 2 b y - 3 c z = 0$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Move all terms not containing $b$ to the right side of the equation.

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Subtract $25$ from both sides of the equation.

$- 2 b y - 3 c z = - 25$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Add $3 c z$ to both sides of the equation.

$- 2 b y = - 25 + 3 c z$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

$- 2 b y = - 25 + 3 c z$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Divide each term in $- 2 b y = - 25 + 3 c z$ by $- 2 y$ and simplify.

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Divide each term in $- 2 b y = - 25 + 3 c z$ by $- 2 y$ .

$\frac{- 2 b y}{- 2 y} = \frac{- 25}{- 2 y} + \frac{3 c z}{- 2 y}$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Simplify the left side.

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Cancel the common factor of $- 2$ .

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Cancel the common factor.

$\frac{- 2 b y}{- 2 y} = \frac{- 25}{- 2 y} + \frac{3 c z}{- 2 y}$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Rewrite the expression.

$\frac{b y}{y} = \frac{- 25}{- 2 y} + \frac{3 c z}{- 2 y}$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

$\frac{b y}{y} = \frac{- 25}{- 2 y} + \frac{3 c z}{- 2 y}$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Cancel the common factor of $y$ .

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Cancel the common factor.

$\frac{b y}{y} = \frac{- 25}{- 2 y} + \frac{3 c z}{- 2 y}$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Divide $b$ by $1$ .

$b = \frac{- 25}{- 2 y} + \frac{3 c z}{- 2 y}$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

$b = \frac{- 25}{- 2 y} + \frac{3 c z}{- 2 y}$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

$b = \frac{- 25}{- 2 y} + \frac{3 c z}{- 2 y}$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Simplify the right side.

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Simplify each term.

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Dividing two negative values results in a positive value.

$b = \frac{25}{(2) y} + \frac{3 c z}{- 2 y}$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Move the negative in front of the fraction.

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

$x = \frac{25}{a} - \frac{b y}{a} - \frac{2 c z}{a}$

Step 3

Solve the equation for $y$ .

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Simplify $a (\frac{25}{a} - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot \frac{y}{a} - \frac{2 c z}{a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z$ .

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Simplify each term.

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Simplify each term.

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Apply the distributive property.

$a (\frac{25}{a} + (- \frac{25}{2 y} + \frac{3 c z}{2 y}) \cdot \frac{y}{a} - \frac{2 c z}{a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Multiply $- - \frac{3 c z}{2 y}$ .

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Multiply $- 1$ by $- 1$ .

$a (\frac{25}{a} + (- \frac{25}{2 y} + 1 (\frac{3 c z}{2 y})) \cdot \frac{y}{a} - \frac{2 c z}{a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Multiply $\frac{3 c z}{2 y}$ by $1$ .

$a (\frac{25}{a} + (- \frac{25}{2 y} + \frac{3 c z}{2 y}) \cdot \frac{y}{a} - \frac{2 c z}{a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

$a (\frac{25}{a} + (- \frac{25}{2 y} + \frac{3 c z}{2 y}) \cdot \frac{y}{a} - \frac{2 c z}{a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Multiply $- \frac{25}{2 y} + \frac{3 c z}{2 y}$ by $\frac{y}{a}$ .

$a (\frac{25}{a} + \frac{(- \frac{25}{2 y} + \frac{3 c z}{2 y}) y}{a} - \frac{2 c z}{a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Combine the numerators over the common denominator.

$a (\frac{25}{a} + \frac{\frac{- 25 + 3 c z}{2 y} \cdot y}{a} - \frac{2 c z}{a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Combine $\frac{- 25 + 3 c z}{2 y}$ and $y$ .

$a (\frac{25}{a} + \frac{\frac{(- 25 + 3 c z) y}{2 y}}{a} - \frac{2 c z}{a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Reduce the expression $\frac{(- 25 + 3 c z) y}{2 y}$ by cancelling the common factors.

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Cancel the common factor.

$a (\frac{25}{a} + \frac{\frac{(- 25 + 3 c z) y}{2 y}}{a} - \frac{2 c z}{a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Rewrite the expression.

$a (\frac{25}{a} + \frac{\frac{- 25 + 3 c z}{2}}{a} - \frac{2 c z}{a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

$a (\frac{25}{a} + \frac{\frac{- 25 + 3 c z}{2}}{a} - \frac{2 c z}{a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Multiply the numerator by the reciprocal of the denominator.

$a (\frac{25}{a} + \frac{- 25 + 3 c z}{2} \cdot \frac{1}{a} - \frac{2 c z}{a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Multiply $\frac{- 25 + 3 c z}{2}$ by $\frac{1}{a}$ .

$a (\frac{25}{a} + \frac{- 25 + 3 c z}{2 a} - \frac{2 c z}{a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

$a (\frac{25}{a} + \frac{- 25 + 3 c z}{2 a} - \frac{2 c z}{a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

To write $\frac{25}{a}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$a (\frac{25}{a} \cdot \frac{2}{2} + \frac{- 25 + 3 c z}{2 a} - \frac{2 c z}{a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Write each expression with a common denominator of $a \cdot 2$ , by multiplying each by an appropriate factor of $1$ .

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Multiply $\frac{25}{a}$ by $\frac{2}{2}$ .

$a (\frac{25 \cdot 2}{a \cdot 2} + \frac{- 25 + 3 c z}{2 a} - \frac{2 c z}{a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Move $2$ to the left of $a$ .

$a (\frac{25 \cdot 2}{2 a} + \frac{- 25 + 3 c z}{2 a} - \frac{2 c z}{a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

$a (\frac{25 \cdot 2}{2 a} + \frac{- 25 + 3 c z}{2 a} - \frac{2 c z}{a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Combine the numerators over the common denominator.

$a (\frac{25 \cdot 2 - 25 + 3 c z}{2 a} - \frac{2 c z}{a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Multiply $25$ by $2$ .

$a (\frac{50 - 25 + 3 c z}{2 a} - \frac{2 c z}{a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Subtract $25$ from $50$ .

$a (\frac{25 + 3 c z}{2 a} - \frac{2 c z}{a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

To write $- \frac{2 c z}{a}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$a (\frac{25 + 3 c z}{2 a} - \frac{2 c z}{a} \cdot \frac{2}{2}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Write each expression with a common denominator of $2 a$ , by multiplying each by an appropriate factor of $1$ .

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Multiply $\frac{2 c z}{a}$ by $\frac{2}{2}$ .

$a (\frac{25 + 3 c z}{2 a} - \frac{2 c z \cdot 2}{a \cdot 2}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Reorder the factors of $a \cdot 2$ .

$a (\frac{25 + 3 c z}{2 a} - \frac{2 c z \cdot 2}{2 a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

$a (\frac{25 + 3 c z}{2 a} - \frac{2 c z \cdot 2}{2 a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Combine the numerators over the common denominator.

$a (\frac{25 + 3 c z - 2 c z \cdot 2}{2 a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Simplify the numerator.

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Multiply $2$ by $- 2$ .

$a (\frac{25 + 3 c z - 4 c z}{2 a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Subtract $4 c z$ from $3 c z$ .

$a (\frac{25 - c z}{2 a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

$a (\frac{25 - c z}{2 a}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Cancel the common factor of $a$ .

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Factor $a$ out of $2 a$ .

$a (\frac{25 - c z}{a \cdot 2}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Cancel the common factor.

$a (\frac{25 - c z}{a \cdot 2}) + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Rewrite the expression.

$\frac{25 - c z}{2} + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

$\frac{25 - c z}{2} + (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Apply the distributive property.

$\frac{25 - c z}{2} + \frac{25}{2 y} \cdot y - \frac{3 c z}{2 y} \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Cancel the common factor of $y$ .

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Factor $y$ out of $2 y$ .

$\frac{25 - c z}{2} + \frac{25}{y \cdot 2} \cdot y - \frac{3 c z}{2 y} \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Cancel the common factor.

$\frac{25 - c z}{2} + \frac{25}{y \cdot 2} \cdot y - \frac{3 c z}{2 y} \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Rewrite the expression.

$\frac{25 - c z}{2} + \frac{25}{2} - \frac{3 c z}{2 y} \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

$\frac{25 - c z}{2} + \frac{25}{2} - \frac{3 c z}{2 y} \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Cancel the common factor of $y$ .

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Move the leading negative in $- \frac{3 c z}{2 y}$ into the numerator.

$\frac{25 - c z}{2} + \frac{25}{2} + \frac{- 3 c z}{2 y} \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Factor $y$ out of $2 y$ .

$\frac{25 - c z}{2} + \frac{25}{2} + \frac{- 3 c z}{y \cdot 2} \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Cancel the common factor.

$\frac{25 - c z}{2} + \frac{25}{2} + \frac{- 3 c z}{y \cdot 2} \cdot y + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Rewrite the expression.

$\frac{25 - c z}{2} + \frac{25}{2} + \frac{- 3 c z}{2} + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

$\frac{25 - c z}{2} + \frac{25}{2} + \frac{- 3 c z}{2} + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Move the negative in front of the fraction.

$\frac{25 - c z}{2} + \frac{25}{2} - \frac{3 c z}{2} + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

$\frac{25 - c z}{2} + \frac{25}{2} - \frac{3 c z}{2} + 2 c z = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Simplify terms.

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Combine the numerators over the common denominator.

$2 c z + \frac{25 - c z + 25 - 3 c z}{2} = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Add $25$ and $25$ .

$2 c z + \frac{- c z + 50 - 3 c z}{2} = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Subtract $3 c z$ from $- c z$ .

$2 c z + \frac{- 4 c z + 50}{2} = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Cancel the common factor of $- 4 c z + 50$ and $2$ .

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Factor $2$ out of $- 4 c z$ .

$2 c z + \frac{2 (- 2 c z) + 50}{2} = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Factor $2$ out of $50$ .

$2 c z + \frac{2 (- 2 c z) + 2 \cdot 25}{2} = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Factor $2$ out of $2 (- 2 c z) + 2 (25)$ .

$2 c z + \frac{2 (- 2 c z + 25)}{2} = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Cancel the common factors.

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Factor $2$ out of $2$ .

$2 c z + \frac{2 (- 2 c z + 25)}{2 (1)} = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Cancel the common factor.

$2 c z + \frac{2 (- 2 c z + 25)}{2 \cdot 1} = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Rewrite the expression.

$2 c z + \frac{- 2 c z + 25}{1} = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Divide $- 2 c z + 25$ by $1$ .

$2 c z - 2 c z + 25 = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

$2 c z - 2 c z + 25 = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

$2 c z - 2 c z + 25 = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Subtract $2 c z$ from $2 c z$ .

$0 + 25 = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Add $0$ and $25$ .

$25 = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

$25 = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

$25 = 25$

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Since $25 = 25$ , the equation will always be true.

Always true

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Always true

$b = \frac{25}{2 y} - \frac{3 c z}{2 y}$

Step 4

Solve the equation for $c$ .

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Simplify $a (\frac{25}{a} - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot \frac{y}{a} - \frac{2 c z}{a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z$ .

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Simplify each term.

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Simplify each term.

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Apply the distributive property.

$a (\frac{25}{a} + (- \frac{25}{2 y} + \frac{3 c z}{2 y}) \cdot \frac{y}{a} - \frac{2 c z}{a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Multiply $- - \frac{3 c z}{2 y}$ .

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Multiply $- 1$ by $- 1$ .

$a (\frac{25}{a} + (- \frac{25}{2 y} + 1 (\frac{3 c z}{2 y})) \cdot \frac{y}{a} - \frac{2 c z}{a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Multiply $\frac{3 c z}{2 y}$ by $1$ .

$a (\frac{25}{a} + (- \frac{25}{2 y} + \frac{3 c z}{2 y}) \cdot \frac{y}{a} - \frac{2 c z}{a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

$a (\frac{25}{a} + (- \frac{25}{2 y} + \frac{3 c z}{2 y}) \cdot \frac{y}{a} - \frac{2 c z}{a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Multiply $- \frac{25}{2 y} + \frac{3 c z}{2 y}$ by $\frac{y}{a}$ .

$a (\frac{25}{a} + \frac{(- \frac{25}{2 y} + \frac{3 c z}{2 y}) y}{a} - \frac{2 c z}{a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Combine the numerators over the common denominator.

$a (\frac{25}{a} + \frac{\frac{- 25 + 3 c z}{2 y} \cdot y}{a} - \frac{2 c z}{a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Combine $\frac{- 25 + 3 c z}{2 y}$ and $y$ .

$a (\frac{25}{a} + \frac{\frac{(- 25 + 3 c z) y}{2 y}}{a} - \frac{2 c z}{a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Reduce the expression $\frac{(- 25 + 3 c z) y}{2 y}$ by cancelling the common factors.

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Cancel the common factor.

$a (\frac{25}{a} + \frac{\frac{(- 25 + 3 c z) y}{2 y}}{a} - \frac{2 c z}{a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Rewrite the expression.

$a (\frac{25}{a} + \frac{\frac{- 25 + 3 c z}{2}}{a} - \frac{2 c z}{a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

$a (\frac{25}{a} + \frac{\frac{- 25 + 3 c z}{2}}{a} - \frac{2 c z}{a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Multiply the numerator by the reciprocal of the denominator.

$a (\frac{25}{a} + \frac{- 25 + 3 c z}{2} \cdot \frac{1}{a} - \frac{2 c z}{a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Multiply $\frac{- 25 + 3 c z}{2}$ by $\frac{1}{a}$ .

$a (\frac{25}{a} + \frac{- 25 + 3 c z}{2 a} - \frac{2 c z}{a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

$a (\frac{25}{a} + \frac{- 25 + 3 c z}{2 a} - \frac{2 c z}{a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

To write $\frac{25}{a}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$a (\frac{25}{a} \cdot \frac{2}{2} + \frac{- 25 + 3 c z}{2 a} - \frac{2 c z}{a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Write each expression with a common denominator of $a \cdot 2$ , by multiplying each by an appropriate factor of $1$ .

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Multiply $\frac{25}{a}$ by $\frac{2}{2}$ .

$a (\frac{25 \cdot 2}{a \cdot 2} + \frac{- 25 + 3 c z}{2 a} - \frac{2 c z}{a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Move $2$ to the left of $a$ .

$a (\frac{25 \cdot 2}{2 a} + \frac{- 25 + 3 c z}{2 a} - \frac{2 c z}{a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

$a (\frac{25 \cdot 2}{2 a} + \frac{- 25 + 3 c z}{2 a} - \frac{2 c z}{a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Combine the numerators over the common denominator.

$a (\frac{25 \cdot 2 - 25 + 3 c z}{2 a} - \frac{2 c z}{a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Multiply $25$ by $2$ .

$a (\frac{50 - 25 + 3 c z}{2 a} - \frac{2 c z}{a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Subtract $25$ from $50$ .

$a (\frac{25 + 3 c z}{2 a} - \frac{2 c z}{a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

To write $- \frac{2 c z}{a}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$a (\frac{25 + 3 c z}{2 a} - \frac{2 c z}{a} \cdot \frac{2}{2}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Write each expression with a common denominator of $2 a$ , by multiplying each by an appropriate factor of $1$ .

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Multiply $\frac{2 c z}{a}$ by $\frac{2}{2}$ .

$a (\frac{25 + 3 c z}{2 a} - \frac{2 c z \cdot 2}{a \cdot 2}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Reorder the factors of $a \cdot 2$ .

$a (\frac{25 + 3 c z}{2 a} - \frac{2 c z \cdot 2}{2 a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

$a (\frac{25 + 3 c z}{2 a} - \frac{2 c z \cdot 2}{2 a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Combine the numerators over the common denominator.

$a (\frac{25 + 3 c z - 2 c z \cdot 2}{2 a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Simplify the numerator.

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Multiply $2$ by $- 2$ .

$a (\frac{25 + 3 c z - 4 c z}{2 a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Subtract $4 c z$ from $3 c z$ .

$a (\frac{25 - c z}{2 a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

$a (\frac{25 - c z}{2 a}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Cancel the common factor of $a$ .

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Factor $a$ out of $2 a$ .

$a (\frac{25 - c z}{a \cdot 2}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Cancel the common factor.

$a (\frac{25 - c z}{a \cdot 2}) - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Rewrite the expression.

$\frac{25 - c z}{2} - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

$\frac{25 - c z}{2} - (\frac{25}{2 y} - \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Apply the distributive property.

$\frac{25 - c z}{2} + (- \frac{25}{2 y} + \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Multiply $- - \frac{3 c z}{2 y}$ .

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Multiply $- 1$ by $- 1$ .

$\frac{25 - c z}{2} + (- \frac{25}{2 y} + 1 (\frac{3 c z}{2 y})) \cdot y - c z = 0$

Always true

Multiply $\frac{3 c z}{2 y}$ by $1$ .

$\frac{25 - c z}{2} + (- \frac{25}{2 y} + \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

$\frac{25 - c z}{2} + (- \frac{25}{2 y} + \frac{3 c z}{2 y}) \cdot y - c z = 0$

Always true

Apply the distributive property.

$\frac{25 - c z}{2} - \frac{25}{2 y} \cdot y + \frac{3 c z}{2 y} \cdot y - c z = 0$

Always true

Cancel the common factor of $y$ .

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Move the leading negative in $- \frac{25}{2 y}$ into the numerator.

$\frac{25 - c z}{2} + \frac{- 25}{2 y} \cdot y + \frac{3 c z}{2 y} \cdot y - c z = 0$

Always true

Factor $y$ out of $2 y$ .

$\frac{25 - c z}{2} + \frac{- 25}{y \cdot 2} \cdot y + \frac{3 c z}{2 y} \cdot y - c z = 0$

Always true

Cancel the common factor.

$\frac{25 - c z}{2} + \frac{- 25}{y \cdot 2} \cdot y + \frac{3 c z}{2 y} \cdot y - c z = 0$

Always true

Rewrite the expression.

$\frac{25 - c z}{2} + \frac{- 25}{2} + \frac{3 c z}{2 y} \cdot y - c z = 0$

Always true

$\frac{25 - c z}{2} + \frac{- 25}{2} + \frac{3 c z}{2 y} \cdot y - c z = 0$

Always true

Cancel the common factor of $y$ .

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Factor $y$ out of $2 y$ .

$\frac{25 - c z}{2} + \frac{- 25}{2} + \frac{3 c z}{y \cdot 2} \cdot y - c z = 0$

Always true

Cancel the common factor.

$\frac{25 - c z}{2} + \frac{- 25}{2} + \frac{3 c z}{y \cdot 2} \cdot y - c z = 0$

Always true

Rewrite the expression.

$\frac{25 - c z}{2} + \frac{- 25}{2} + \frac{3 c z}{2} - c z = 0$

Always true

$\frac{25 - c z}{2} + \frac{- 25}{2} + \frac{3 c z}{2} - c z = 0$

Always true

Move the negative in front of the fraction.

$\frac{25 - c z}{2} - \frac{25}{2} + \frac{3 c z}{2} - c z = 0$

Always true

$\frac{25 - c z}{2} - \frac{25}{2} + \frac{3 c z}{2} - c z = 0$

Always true

Simplify terms.

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Combine the numerators over the common denominator.

$- c z + \frac{25 - c z - 25 + 3 c z}{2} = 0$

Always true

Combine the opposite terms in $25 - c z - 25 + 3 c z$ .

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Subtract $25$ from $25$ .

$- c z + \frac{- c z + 0 + 3 c z}{2} = 0$

Always true

Add $- c z$ and $0$ .

$- c z + \frac{- c z + 3 c z}{2} = 0$

Always true

$- c z + \frac{- c z + 3 c z}{2} = 0$

Always true

Add $- c z$ and $3 c z$ .

$- c z + \frac{2 c z}{2} = 0$

Always true

Cancel the common factor of $2$ .

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Cancel the common factor.

$- c z + \frac{2 c z}{2} = 0$

Always true

Divide $c z$ by $1$ .

$- c z + c z = 0$

Always true

$- c z + c z = 0$

Always true

Add $- c z$ and $c z$ .

$0 = 0$

Always true

$0 = 0$

Always true

$0 = 0$

Always true

Since $0 = 0$ , the equation will always be true.

Always true