Precalculus Examples

$\log_{25} (5) + \log_{25} (3125)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{25} (5 \cdot 3125)$

Step 2

Multiply $5$ by $3125$ .

$\log_{25} (15625)$

Step 3

Logarithm base $25$ of $15625$ is $3$ .

$3$