Precalculus Examples

$\log_{88} (11) + \log_{88} (8)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{88} (11 \cdot 8)$

Step 2

Multiply $11$ by $8$ .

$\log_{88} (88)$

Step 3

Logarithm base $88$ of $88$ is $1$ .

$1$