Precalculus Examples

$\log_{8} (16) + \log_{8} (2)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{8} (16 \cdot 2)$

Step 2

Multiply $16$ by $2$ .

$\log_{8} (32)$

Step 3

Logarithm base $8$ of $32$ is $\frac{5}{3}$ .

$\frac{5}{3}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$\frac{5}{3}$

Decimal Form:

$1.\overline{6}$

Mixed Number Form:

$1 \frac{2}{3}$