Precalculus Examples

$1 \cdot \ln (x) + x \cdot \frac{1}{x} - 1$

Step 1

Simplify each term.

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Step 1.1

Multiply $\ln (x)$ by $1$ .

$\ln (x) + x \cdot \frac{1}{x} - 1$

Step 1.2

Cancel the common factor of $x$ .

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Step 1.2.1

Cancel the common factor.

$\ln (x) + x \cdot \frac{1}{x} - 1$

Step 1.2.2

Rewrite the expression.

$\ln (x) + 1 - 1$

$\ln (x) + 1 - 1$

$\ln (x) + 1 - 1$

Step 2

Combine the opposite terms in $\ln (x) + 1 - 1$ .

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Step 2.1

Subtract $1$ from $1$ .

$\ln (x) + 0$

Step 2.2

Add $\ln (x)$ and $0$ .

$\ln (x)$

$\ln (x)$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$