Precalculus Examples

$\log_{a} (16) + \frac{2}{5} \cdot \log_{a} (18) - \frac{2}{5} \cdot \log_{a} (9) + \log_{a} (\frac{1}{2^{\frac{12}{5}}})$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\frac{2}{5} \cdot \log_{a} (18) - \frac{2}{5} \cdot \log_{a} (9) + \log_{a} (16 \frac{1}{2^{\frac{12}{5}}})$

Step 2

Simplify each term.

Tap for more steps...

Step 2.1

Simplify $\frac{2}{5} \log_{a} (18)$ by moving $\frac{2}{5}$ inside the logarithm.

$\log_{a} (18^{\frac{2}{5}}) - \frac{2}{5} \cdot \log_{a} (9) + \log_{a} (16 \frac{1}{2^{\frac{12}{5}}})$

Step 2.2

Combine $\log_{a} (9)$ and $\frac{2}{5}$ .

$\log_{a} (18^{\frac{2}{5}}) - \frac{\log_{a} (9) \cdot 2}{5} + \log_{a} (16 \frac{1}{2^{\frac{12}{5}}})$

Step 2.3

Rewrite $\frac{\log_{a} (9) \cdot 2}{5}$ as $\frac{2}{5} \log_{a} (9)$ .

$\log_{a} (18^{\frac{2}{5}}) - (\frac{2}{5} \log_{a} (9)) + \log_{a} (16 \frac{1}{2^{\frac{12}{5}}})$

Step 2.4

Simplify $\frac{2}{5} \log_{a} (9)$ by moving $\frac{2}{5}$ inside the logarithm.

$\log_{a} (18^{\frac{2}{5}}) - \log_{a} (9^{\frac{2}{5}}) + \log_{a} (16 \frac{1}{2^{\frac{12}{5}}})$

Step 2.5

Combine $16$ and $\frac{1}{2^{\frac{12}{5}}}$ .

$\log_{a} (18^{\frac{2}{5}}) - \log_{a} (9^{\frac{2}{5}}) + \log_{a} (\frac{16}{2^{\frac{12}{5}}})$

Step 3

Use the quotient property of logarithms, $\log_{b} (x) - \log_{b} (y) = \log_{b} (\frac{x}{y})$ .

$\log_{a} (\frac{18^{\frac{2}{5}}}{9^{\frac{2}{5}}}) + \log_{a} (\frac{16}{2^{\frac{12}{5}}})$

Step 4

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{a} (\frac{18^{\frac{2}{5}}}{9^{\frac{2}{5}}} \cdot \frac{16}{2^{\frac{12}{5}}})$

Step 5

Combine.

$\log_{a} (\frac{18^{\frac{2}{5}} \cdot 16}{9^{\frac{2}{5}} \cdot 2^{\frac{12}{5}}})$

Step 6

Move $16$ to the left of $18^{\frac{2}{5}}$ .

$\log_{a} (\frac{16 \cdot 18^{\frac{2}{5}}}{9^{\frac{2}{5}} \cdot 2^{\frac{12}{5}}})$