Precalculus Examples

$\log_{5} (8) \cdot \log_{8} (0.04)$

Step 1

Log base $8$ of $0.04$ is approximately $- 1.54795206$ .

$\log_{5} (8) \cdot - 1.54795206$

Step 2

Multiply $\log_{5} (8) \cdot - 1.54795206$ .

Tap for more steps...

Step 2.1

Reorder $\log_{5} (8)$ and $- 1.54795206$ .

$- 1.54795206 \cdot \log_{5} (8)$

Step 2.2

Simplify $- 1.54795206 \cdot \log_{5} (8)$ by moving $1.54795206$ inside the logarithm.

$- \log_{5} (8^{1.54795206})$

Step 3

Raise $8$ to the power of $1.54795206$ .

$- \log_{5} (25)$

Step 4

Log base $5$ of $25$ is approximately $2$ .

$- 1 \cdot 2$

Step 5

Multiply $- 1$ by $2$ .

$- 2$