Precalculus Examples

$\log_{3} (81) + \log_{3} (81)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{3} (81 \cdot 81)$

Step 2

Multiply $81$ by $81$ .

$\log_{3} (6561)$

Step 3

Logarithm base $3$ of $6561$ is $8$ .

$8$