Precalculus Examples

$\log_{4} (7.416 - 3) + \log_{4} (7.416 - 3)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{4} ((7.416 - 3) (7.416 - 3))$

Step 2

Subtract $3$ from $7.416$ .

$\log_{4} (4.416 (7.416 - 3))$

Step 3

Subtract $3$ from $7.416$ .

$\log_{4} (4.416 \cdot 4.416)$

Step 4

Multiply $4.416$ by $4.416$ .

$\log_{4} (19.501056)$

Step 5

Log base $4$ of $19.501056$ is approximately $2.14274017$ .

$2.14274017$