Precalculus Examples

$4 \log_{7} (x + 7) - \log_{7} (x - 13) - \log_{7} (x - 18)$

Step 1

Simplify $4 \log_{7} (x + 7)$ by moving $4$ inside the logarithm.

$\log_{7} ({(x + 7)}^{4}) - \log_{7} (x - 13) - \log_{7} (x - 18)$

Step 2

Use the quotient property of logarithms, $\log_{b} (x) - \log_{b} (y) = \log_{b} (\frac{x}{y})$ .

$\log_{7} (\frac{{(x + 7)}^{4}}{x - 13}) - \log_{7} (x - 18)$

Step 3

Use the quotient property of logarithms, $\log_{b} (x) - \log_{b} (y) = \log_{b} (\frac{x}{y})$ .

$\log_{7} (\frac{\frac{{(x + 7)}^{4}}{x - 13}}{x - 18})$

Step 4

Multiply the numerator by the reciprocal of the denominator.

$\log_{7} (\frac{{(x + 7)}^{4}}{x - 13} \cdot \frac{1}{x - 18})$

Step 5

Multiply $\frac{{(x + 7)}^{4}}{x - 13}$ by $\frac{1}{x - 18}$ .

$\log_{7} (\frac{{(x + 7)}^{4}}{(x - 13) (x - 18)})$