Precalculus Examples

$\log (0.01) + \log (1000)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log (0.01 \cdot 1000)$

Step 2

Multiply $0.01$ by $1000$ .

$\log (10)$

Step 3

Log base $10$ of $10$ is approximately $1$ .

$1$