Precalculus Examples

$\frac{1}{3} \cdot \ln (2 x - 3) + \frac{1}{3} \cdot \ln (3 x + 2) - (\frac{2}{3} \cdot \ln (x^{2}) - 1)$

Step 1

Simplify each term.

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Step 1.1

Simplify $\frac{1}{3} \ln (2 x - 3)$ by moving $\frac{1}{3}$ inside the logarithm.

$\ln ({(2 x - 3)}^{\frac{1}{3}}) + \frac{1}{3} \cdot \ln (3 x + 2) - (\frac{2}{3} \cdot \ln (x^{2}) - 1)$

Step 1.2

Simplify $\frac{1}{3} \ln (3 x + 2)$ by moving $\frac{1}{3}$ inside the logarithm.

$\ln ({(2 x - 3)}^{\frac{1}{3}}) + \ln ({(3 x + 2)}^{\frac{1}{3}}) - (\frac{2}{3} \cdot \ln (x^{2}) - 1)$

Step 1.3

Simplify each term.

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Step 1.3.1

Simplify $\frac{2}{3} \ln (x^{2})$ by moving $\frac{2}{3}$ inside the logarithm.

$\ln ({(2 x - 3)}^{\frac{1}{3}}) + \ln ({(3 x + 2)}^{\frac{1}{3}}) - (\ln ({(x^{2})}^{\frac{2}{3}}) - 1)$

Step 1.3.2

Multiply the exponents in ${(x^{2})}^{\frac{2}{3}}$ .

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Step 1.3.2.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\ln ({(2 x - 3)}^{\frac{1}{3}}) + \ln ({(3 x + 2)}^{\frac{1}{3}}) - (\ln (x^{2 (\frac{2}{3})}) - 1)$

Step 1.3.2.2

Multiply $2 (\frac{2}{3})$ .

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Step 1.3.2.2.1

Combine $2$ and $\frac{2}{3}$ .

$\ln ({(2 x - 3)}^{\frac{1}{3}}) + \ln ({(3 x + 2)}^{\frac{1}{3}}) - (\ln (x^{\frac{2 \cdot 2}{3}}) - 1)$

Step 1.3.2.2.2

Multiply $2$ by $2$ .

$\ln ({(2 x - 3)}^{\frac{1}{3}}) + \ln ({(3 x + 2)}^{\frac{1}{3}}) - (\ln (x^{\frac{4}{3}}) - 1)$

Step 1.4

Apply the distributive property.

$\ln ({(2 x - 3)}^{\frac{1}{3}}) + \ln ({(3 x + 2)}^{\frac{1}{3}}) - \ln (x^{\frac{4}{3}}) - - 1$

Step 1.5

Multiply $- 1$ by $- 1$ .

$\ln ({(2 x - 3)}^{\frac{1}{3}}) + \ln ({(3 x + 2)}^{\frac{1}{3}}) - \ln (x^{\frac{4}{3}}) + 1$

Step 2

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\ln ({(2 x - 3)}^{\frac{1}{3}} {(3 x + 2)}^{\frac{1}{3}}) - \ln (x^{\frac{4}{3}}) + 1$

Step 3

Use the quotient property of logarithms, $\log_{b} (x) - \log_{b} (y) = \log_{b} (\frac{x}{y})$ .

$\ln (\frac{{(2 x - 3)}^{\frac{1}{3}} {(3 x + 2)}^{\frac{1}{3}}}{x^{\frac{4}{3}}}) + 1$