Precalculus Examples

$\log (3.2) + \log (5.7)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log (3.2 \cdot 5.7)$

Step 2

Multiply $3.2$ by $5.7$ .

$\log (18.24)$

Step 3

Log base $10$ of $18.24$ is approximately $1.26102483$ .

$1.26102483$