Precalculus Examples

$\frac{1}{4} \cdot \ln (2) - \frac{14999 \ln (p)}{8}$

Step 1

Simplify each term.

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Step 1.1

Simplify $\frac{1}{4} \ln (2)$ by moving $\frac{1}{4}$ inside the logarithm.

$\ln (2^{\frac{1}{4}}) - \frac{14999 \ln (p)}{8}$

Step 1.2

Rewrite $\frac{14999 \ln (p)}{8}$ as $\frac{14999}{8} \ln (p)$ .

$\ln (2^{\frac{1}{4}}) - (\frac{14999}{8} \ln (p))$

Step 1.3

Simplify $\frac{14999}{8} \ln (p)$ by moving $\frac{14999}{8}$ inside the logarithm.

$\ln (2^{\frac{1}{4}}) - \ln (p^{\frac{14999}{8}})$

Step 2

Use the quotient property of logarithms, $\log_{b} (x) - \log_{b} (y) = \log_{b} (\frac{x}{y})$ .

$\ln (\frac{2^{\frac{1}{4}}}{p^{\frac{14999}{8}}})$