Precalculus Examples

$\frac{1}{6} \cdot (\log_{2} (x) + \log_{2} (y))$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\frac{1}{6} \cdot \log_{2} (x y)$

Step 2

Simplify $\frac{1}{6} \log_{2} (x y)$ by moving $\frac{1}{6}$ inside the logarithm.

$\log_{2} ({(x y)}^{\frac{1}{6}})$

Step 3

Apply the product rule to $x y$ .

$\log_{2} (x^{\frac{1}{6}} y^{\frac{1}{6}})$