Precalculus Examples

$e^{- 0.37 \cdot 1.6} + \ln (1.6) + 1.41 \cos (1.6)$

Step 1

Simplify each term.

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Step 1.1

Multiply $- 0.37$ by $1.6$ .

$e^{- 0.592} + \ln (1.6) + 1.41 \cos (1.6)$

Step 1.2

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{e^{0.592}} + \ln (1.6) + 1.41 \cos (1.6)$

Step 1.3

Multiply $1.41$ by $\cos (1.6)$ .

$\frac{1}{e^{0.592}} + \ln (1.6) - 0.04117132$

Step 2

Simplify by adding terms.

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Step 2.1

Subtract $0.04117132$ from $\frac{1}{e^{0.592}}$ .

$0.51204841 + \ln (1.6)$

Step 2.2

Add $0.51204841$ and $\ln (1.6)$ .

$0.98205204$