Precalculus Examples

$\frac{7 e^{\ln (2) + \ln (3)}}{2} - 15$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\frac{7 e^{\ln (2 \cdot 3)}}{2} - 15$

Step 2

Multiply $2$ by $3$ .

$\frac{7 e^{\ln (6)}}{2} - 15$

Step 3

Simplify each term.

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Step 3.1

Exponentiation and log are inverse functions.

$\frac{7 \cdot 6}{2} - 15$

Step 3.2

Multiply $7$ by $6$ .

$\frac{42}{2} - 15$

Step 3.3

Divide $42$ by $2$ .

$21 - 15$

Step 4

Subtract $15$ from $21$ .

$6$