Precalculus Examples

$\frac{\ln (2)}{3.5} t$

Step 1

Replace $e$ with an approximation.

$\frac{\log_{2.71828182} (2)}{3.5} t$

Step 2

Log base $2.71828182$ of $2$ is approximately $0.69314718$ .

$\frac{0.69314718}{3.5} t$

Step 3

Divide $0.69314718$ by $3.5$ .

$0.19804205 t$