Precalculus Examples

$\log_{108} (6) + \log_{108} (18)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{108} (6 \cdot 18)$

Step 2

Multiply $6$ by $18$ .

$\log_{108} (108)$

Step 3

Logarithm base $108$ of $108$ is $1$ .

$1$