Precalculus Examples

$\log_{16} (2^{1.9}) + e^{3 \ln (10)}$

Step 1

Simplify each term.

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Step 1.1

Raise $2$ to the power of $1.9$ .

$\log_{16} (3.73213196) + e^{3 \ln (10)}$

Step 1.2

Log base $16$ of $3.73213196$ is approximately $0.475$ .

$0.475 + e^{3 \ln (10)}$

Step 1.3

Simplify $3 \ln (10)$ by moving $3$ inside the logarithm.

$0.475 + e^{\ln (10^{3})}$

Step 1.4

Exponentiation and log are inverse functions.

$0.475 + 10^{3}$

Step 1.5

Raise $10$ to the power of $3$ .

$0.475 + 1000$

Step 2

Add $0.475$ and $1000$ .

$1000.475$