Precalculus Examples

$\log_{15} (9) + \log_{15} (25)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{15} (9 \cdot 25)$

Step 2

Multiply $9$ by $25$ .

$\log_{15} (225)$

Step 3

Logarithm base $15$ of $225$ is $2$ .

$2$