Precalculus Examples

$\frac{\tan (\frac{π}{2}) - \tan (\frac{π}{6})}{1 + \tan (\frac{π}{2}) \tan (\frac{π}{6})}$

Step 1

Rewrite $\tan (\frac{π}{2})$ in terms of sines and cosines.

$\frac{\frac{\sin (\frac{π}{2})}{\cos (\frac{π}{2})} - \tan (\frac{π}{6})}{1 + \tan (\frac{π}{2}) \tan (\frac{π}{6})}$

Step 2

The exact value of $\cos (\frac{π}{2})$ is $0$ .

$\frac{\frac{\sin (\frac{π}{2})}{0} - \tan (\frac{π}{6})}{1 + \tan (\frac{π}{2}) \tan (\frac{π}{6})}$

Step 3

The expression contains a division by $0$ . The expression is undefined.

Undefined