Precalculus Examples

$[\begin{array}{c} x & y & z \\ a & b & c \\ 2 & 4 & 5 \end{array}] = 3 [\begin{array}{c} 2 & 4 & 5 \\ 3 a & 3 b & 3 c \\ x - 2 & y - 4 & z - 5 \end{array}]$

Step 1

Multiply $3$ by each element of the matrix.

$[\begin{array}{c} x & y & z \\ a & b & c \\ 2 & 4 & 5 \end{array}] = [\begin{array}{c} 3 \cdot 2 & 3 \cdot 4 & 3 \cdot 5 \\ 3 (3 a) & 3 (3 b) & 3 (3 c) \\ 3 (x - 2) & 3 (y - 4) & 3 (z - 5) \end{array}]$

Step 2

Simplify each element in the matrix.

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Step 2.1

Multiply $3$ by $2$ .

$[\begin{array}{c} x & y & z \\ a & b & c \\ 2 & 4 & 5 \end{array}] = [\begin{array}{c} 6 & 3 \cdot 4 & 3 \cdot 5 \\ 3 (3 a) & 3 (3 b) & 3 (3 c) \\ 3 (x - 2) & 3 (y - 4) & 3 (z - 5) \end{array}]$

Step 2.2

Multiply $3$ by $4$ .

$[\begin{array}{c} x & y & z \\ a & b & c \\ 2 & 4 & 5 \end{array}] = [\begin{array}{c} 6 & 12 & 3 \cdot 5 \\ 3 (3 a) & 3 (3 b) & 3 (3 c) \\ 3 (x - 2) & 3 (y - 4) & 3 (z - 5) \end{array}]$

Step 2.3

Multiply $3$ by $5$ .

$[\begin{array}{c} x & y & z \\ a & b & c \\ 2 & 4 & 5 \end{array}] = [\begin{array}{c} 6 & 12 & 15 \\ 3 (3 a) & 3 (3 b) & 3 (3 c) \\ 3 (x - 2) & 3 (y - 4) & 3 (z - 5) \end{array}]$

Step 2.4

Multiply $3$ by $3$ .

$[\begin{array}{c} x & y & z \\ a & b & c \\ 2 & 4 & 5 \end{array}] = [\begin{array}{c} 6 & 12 & 15 \\ 9 a & 3 (3 b) & 3 (3 c) \\ 3 (x - 2) & 3 (y - 4) & 3 (z - 5) \end{array}]$

Step 2.5

Multiply $3$ by $3$ .

$[\begin{array}{c} x & y & z \\ a & b & c \\ 2 & 4 & 5 \end{array}] = [\begin{array}{c} 6 & 12 & 15 \\ 9 a & 9 b & 3 (3 c) \\ 3 (x - 2) & 3 (y - 4) & 3 (z - 5) \end{array}]$

Step 2.6

Multiply $3$ by $3$ .

$[\begin{array}{c} x & y & z \\ a & b & c \\ 2 & 4 & 5 \end{array}] = [\begin{array}{c} 6 & 12 & 15 \\ 9 a & 9 b & 9 c \\ 3 (x - 2) & 3 (y - 4) & 3 (z - 5) \end{array}]$

Step 2.7

Apply the distributive property.

$[\begin{array}{c} x & y & z \\ a & b & c \\ 2 & 4 & 5 \end{array}] = [\begin{array}{c} 6 & 12 & 15 \\ 9 a & 9 b & 9 c \\ 3 x + 3 \cdot - 2 & 3 (y - 4) & 3 (z - 5) \end{array}]$

Step 2.8

Multiply $3$ by $- 2$ .

$[\begin{array}{c} x & y & z \\ a & b & c \\ 2 & 4 & 5 \end{array}] = [\begin{array}{c} 6 & 12 & 15 \\ 9 a & 9 b & 9 c \\ 3 x - 6 & 3 (y - 4) & 3 (z - 5) \end{array}]$

Step 2.9

Apply the distributive property.

$[\begin{array}{c} x & y & z \\ a & b & c \\ 2 & 4 & 5 \end{array}] = [\begin{array}{c} 6 & 12 & 15 \\ 9 a & 9 b & 9 c \\ 3 x - 6 & 3 y + 3 \cdot - 4 & 3 (z - 5) \end{array}]$

Step 2.10

Multiply $3$ by $- 4$ .

$[\begin{array}{c} x & y & z \\ a & b & c \\ 2 & 4 & 5 \end{array}] = [\begin{array}{c} 6 & 12 & 15 \\ 9 a & 9 b & 9 c \\ 3 x - 6 & 3 y - 12 & 3 (z - 5) \end{array}]$

Step 2.11

Apply the distributive property.

$[\begin{array}{c} x & y & z \\ a & b & c \\ 2 & 4 & 5 \end{array}] = [\begin{array}{c} 6 & 12 & 15 \\ 9 a & 9 b & 9 c \\ 3 x - 6 & 3 y - 12 & 3 z + 3 \cdot - 5 \end{array}]$

Step 2.12

Multiply $3$ by $- 5$ .

$[\begin{array}{c} x & y & z \\ a & b & c \\ 2 & 4 & 5 \end{array}] = [\begin{array}{c} 6 & 12 & 15 \\ 9 a & 9 b & 9 c \\ 3 x - 6 & 3 y - 12 & 3 z - 15 \end{array}]$

Step 3

Write as a linear system of equations.

$x = 6$

$y = 12$

$z = 15$

$a = 9 a$

$b = 9 b$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

Step 4

Solve the system of equations.

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Step 4.1

Replace all occurrences of $x$ with $6$ in each equation.

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Step 4.1.1

Move all terms containing $a$ to the left side of the equation.

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Step 4.1.1.1

Subtract $9 a$ from both sides of the equation.

$a - 9 a = 0$

$x = 6$

$y = 12$

$z = 15$

$b = 9 b$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

Step 4.1.1.2

Subtract $9 a$ from $a$ .

$- 8 a = 0$

$x = 6$

$y = 12$

$z = 15$

$b = 9 b$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

$- 8 a = 0$

$x = 6$

$y = 12$

$z = 15$

$b = 9 b$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

Step 4.1.2

Divide each term in $- 8 a = 0$ by $- 8$ and simplify.

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Step 4.1.2.1

Divide each term in $- 8 a = 0$ by $- 8$ .

$\frac{- 8 a}{- 8} = \frac{0}{- 8}$

$x = 6$

$y = 12$

$z = 15$

$b = 9 b$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

Step 4.1.2.2

Simplify the left side.

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Step 4.1.2.2.1

Cancel the common factor of $- 8$ .

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Step 4.1.2.2.1.1

Cancel the common factor.

$\frac{- 8 a}{- 8} = \frac{0}{- 8}$

$x = 6$

$y = 12$

$z = 15$

$b = 9 b$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

Step 4.1.2.2.1.2

Divide $a$ by $1$ .

$a = \frac{0}{- 8}$

$x = 6$

$y = 12$

$z = 15$

$b = 9 b$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

$a = \frac{0}{- 8}$

$x = 6$

$y = 12$

$z = 15$

$b = 9 b$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

$a = \frac{0}{- 8}$

$x = 6$

$y = 12$

$z = 15$

$b = 9 b$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

Step 4.1.2.3

Simplify the right side.

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Step 4.1.2.3.1

Divide $0$ by $- 8$ .

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$b = 9 b$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$b = 9 b$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$b = 9 b$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

Step 4.1.3

Move all terms containing $b$ to the left side of the equation.

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Step 4.1.3.1

Subtract $9 b$ from both sides of the equation.

$b - 9 b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

Step 4.1.3.2

Subtract $9 b$ from $b$ .

$- 8 b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

$- 8 b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

Step 4.1.4

Divide each term in $- 8 b = 0$ by $- 8$ and simplify.

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Step 4.1.4.1

Divide each term in $- 8 b = 0$ by $- 8$ .

$\frac{- 8 b}{- 8} = \frac{0}{- 8}$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

Step 4.1.4.2

Simplify the left side.

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Step 4.1.4.2.1

Cancel the common factor of $- 8$ .

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Step 4.1.4.2.1.1

Cancel the common factor.

$\frac{- 8 b}{- 8} = \frac{0}{- 8}$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

Step 4.1.4.2.1.2

Divide $b$ by $1$ .

$b = \frac{0}{- 8}$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

$b = \frac{0}{- 8}$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

$b = \frac{0}{- 8}$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

Step 4.1.4.3

Simplify the right side.

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Step 4.1.4.3.1

Divide $0$ by $- 8$ .

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$c = 9 c$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

Step 4.1.5

Move all terms containing $c$ to the left side of the equation.

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Step 4.1.5.1

Subtract $9 c$ from both sides of the equation.

$c - 9 c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

Step 4.1.5.2

Subtract $9 c$ from $c$ .

$- 8 c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

$- 8 c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

Step 4.1.6

Divide each term in $- 8 c = 0$ by $- 8$ and simplify.

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Step 4.1.6.1

Divide each term in $- 8 c = 0$ by $- 8$ .

$\frac{- 8 c}{- 8} = \frac{0}{- 8}$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

Step 4.1.6.2

Simplify the left side.

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Step 4.1.6.2.1

Cancel the common factor of $- 8$ .

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Step 4.1.6.2.1.1

Cancel the common factor.

$\frac{- 8 c}{- 8} = \frac{0}{- 8}$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

Step 4.1.6.2.1.2

Divide $c$ by $1$ .

$c = \frac{0}{- 8}$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

$c = \frac{0}{- 8}$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

$c = \frac{0}{- 8}$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

Step 4.1.6.3

Simplify the right side.

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Step 4.1.6.3.1

Divide $0$ by $- 8$ .

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$2 = 3 x - 6$

$4 = 3 y - 12$

$5 = 3 z - 15$

Step 4.1.7

Replace all occurrences of $x$ in $2 = 3 x - 6$ with $6$ .

$2 = 3 (6) - 6$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$4 = 3 y - 12$

$5 = 3 z - 15$

Step 4.1.8

Simplify the right side.

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Step 4.1.8.1

Simplify $3 (6) - 6$ .

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Step 4.1.8.1.1

Multiply $3$ by $6$ .

$2 = 18 - 6$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$4 = 3 y - 12$

$5 = 3 z - 15$

Step 4.1.8.1.2

Subtract $6$ from $18$ .

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$4 = 3 y - 12$

$5 = 3 z - 15$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$4 = 3 y - 12$

$5 = 3 z - 15$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$4 = 3 y - 12$

$5 = 3 z - 15$

Step 4.1.9

Rewrite the equation as $3 y - 12 = 4$ .

$3 y - 12 = 4$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$5 = 3 z - 15$

Step 4.1.10

Move all terms not containing $y$ to the right side of the equation.

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Step 4.1.10.1

Add $12$ to both sides of the equation.

$3 y = 4 + 12$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$5 = 3 z - 15$

Step 4.1.10.2

Add $4$ and $12$ .

$3 y = 16$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$5 = 3 z - 15$

$3 y = 16$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$5 = 3 z - 15$

Step 4.1.11

Divide each term in $3 y = 16$ by $3$ and simplify.

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Step 4.1.11.1

Divide each term in $3 y = 16$ by $3$ .

$\frac{3 y}{3} = \frac{16}{3}$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$5 = 3 z - 15$

Step 4.1.11.2

Simplify the left side.

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Step 4.1.11.2.1

Cancel the common factor of $3$ .

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Step 4.1.11.2.1.1

Cancel the common factor.

$\frac{3 y}{3} = \frac{16}{3}$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$5 = 3 z - 15$

Step 4.1.11.2.1.2

Divide $y$ by $1$ .

$y = \frac{16}{3}$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$5 = 3 z - 15$

$y = \frac{16}{3}$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$5 = 3 z - 15$

$y = \frac{16}{3}$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$5 = 3 z - 15$

$y = \frac{16}{3}$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$5 = 3 z - 15$

Step 4.1.12

Rewrite the equation as $3 z - 15 = 5$ .

$3 z - 15 = 5$

$y = \frac{16}{3}$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

Step 4.1.13

Move all terms not containing $z$ to the right side of the equation.

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Step 4.1.13.1

Add $15$ to both sides of the equation.

$3 z = 5 + 15$

$y = \frac{16}{3}$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

Step 4.1.13.2

Add $5$ and $15$ .

$3 z = 20$

$y = \frac{16}{3}$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$3 z = 20$

$y = \frac{16}{3}$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

Step 4.1.14

Divide each term in $3 z = 20$ by $3$ and simplify.

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Step 4.1.14.1

Divide each term in $3 z = 20$ by $3$ .

$\frac{3 z}{3} = \frac{20}{3}$

$y = \frac{16}{3}$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

Step 4.1.14.2

Simplify the left side.

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Step 4.1.14.2.1

Cancel the common factor of $3$ .

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Step 4.1.14.2.1.1

Cancel the common factor.

$\frac{3 z}{3} = \frac{20}{3}$

$y = \frac{16}{3}$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

Step 4.1.14.2.1.2

Divide $z$ by $1$ .

$z = \frac{20}{3}$

$y = \frac{16}{3}$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$z = \frac{20}{3}$

$y = \frac{16}{3}$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$z = \frac{20}{3}$

$y = \frac{16}{3}$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$z = \frac{20}{3}$

$y = \frac{16}{3}$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

$z = \frac{20}{3}$

$y = \frac{16}{3}$

$2 = 12$

$c = 0$

$b = 0$

$a = 0$

$x = 6$

$y = 12$

$z = 15$

Step 4.2

Since $2 = 12$ is not true, there is no solution.

$No solution$