Precalculus Examples

$\log_{2} (0.04) + 2 \log_{2} (5)$

Step 1

Log base $2$ of $0.04$ is approximately $- 4.64385618$ .

$- 4.64385618 + 2 \log_{2} (5)$

Step 2

Simplify $2 \log_{2} (5)$ by moving $2$ inside the logarithm.

$- 4.64385618 + \log_{2} (5^{2})$

Step 3

Raise $5$ to the power of $2$ .

$- 4.64385618 + \log_{2} (25)$

Step 4

The result can be shown in multiple forms.

Exact Form:

$- 4.64385618 + \log_{2} (25)$

Decimal Form:

$4.44089209 \cdot 10^{- 15}$