Precalculus Examples

$\log_{14} (2) + \log_{14} (7)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{14} (2 \cdot 7)$

Step 2

Multiply $2$ by $7$ .

$\log_{14} (14)$

Step 3

Logarithm base $14$ of $14$ is $1$ .

$1$