Pre-Algebra Examples

$\frac{11 x^{2} \cdot (33 x^{3})}{4 x + 12 x^{2}}$

Step 1

Expand $11 x^{2} \cdot (33 x^{3})$ .

Tap for more steps...

Step 1.1

Remove parentheses.

$\frac{11 x^{2} \cdot (33 x^{3})}{4 x + 12 x^{2}}$

Step 1.2

Move $x^{2}$ .

$\frac{11 \cdot (33 x^{2} x^{3})}{4 x + 12 x^{2}}$

Step 1.3

Multiply $11$ by $33$ .

$\frac{363 x^{2} x^{3}}{4 x + 12 x^{2}}$

Step 1.4

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{363 x^{2 + 3}}{4 x + 12 x^{2}}$

Step 1.5

Add $2$ and $3$ .

$\frac{363 x^{5}}{4 x + 12 x^{2}}$

Step 2

Reorder $4 x$ and $12 x^{2}$ .

$\frac{363 x^{5}}{12 x^{2} + 4 x}$

Step 3

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$12 x^{2}$

$4 x$

$0$

$363 x^{5}$

$0 x^{4}$

$0 x^{3}$

$0 x^{2}$

$0 x$

$0$

Step 4

Divide the highest order term in the dividend $363 x^{5}$ by the highest order term in divisor $12 x^{2}$ .

$\frac{121 x^{3}}{4}$

$12 x^{2}$

$4 x$

$0$

$363 x^{5}$

$0 x^{4}$

$0 x^{3}$

$0 x^{2}$

$0 x$

$0$

Step 5

Multiply the new quotient term by the divisor.

$\frac{121 x^{3}}{4}$

$12 x^{2}$

$4 x$

$0$

$363 x^{5}$

$0 x^{4}$

$0 x^{3}$

$0 x^{2}$

$0 x$

$0$

$363 x^{5}$

$121 x^{4}$

$0$

Step 6

The expression needs to be subtracted from the dividend, so change all the signs in $363 x^{5} + 121 x^{4} + 0$

$\frac{121 x^{3}}{4}$

$12 x^{2}$

$4 x$

$0$

$363 x^{5}$

$0 x^{4}$

$0 x^{3}$

$0 x^{2}$

$0 x$

$0$

$363 x^{5}$

$121 x^{4}$

$0$

Step 7

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$\frac{121 x^{3}}{4}$

$12 x^{2}$

$4 x$

$0$

$363 x^{5}$

$0 x^{4}$

$0 x^{3}$

$0 x^{2}$

$0 x$

$0$

$363 x^{5}$

$121 x^{4}$

$0$

$121 x^{4}$

$0$

Step 8

Pull the next term from the original dividend down into the current dividend.

$\frac{121 x^{3}}{4}$

$12 x^{2}$

$4 x$

$0$

$363 x^{5}$

$0 x^{4}$

$0 x^{3}$

$0 x^{2}$

$0 x$

$0$

$363 x^{5}$

$121 x^{4}$

$0$

$121 x^{4}$

$0$

$0 x^{2}$

$0 x$

Step 9

Divide the highest order term in the dividend $- 121 x^{4}$ by the highest order term in divisor $12 x^{2}$ .

$\frac{121 x^{3}}{4}$

$\frac{121 x^{2}}{12}$

$12 x^{2}$

$4 x$

$0$

$363 x^{5}$

$0 x^{4}$

$0 x^{3}$

$0 x^{2}$

$0 x$

$0$

$363 x^{5}$

$121 x^{4}$

$0$

$121 x^{4}$

$0$

$0 x^{2}$

$0 x$

Step 10

Multiply the new quotient term by the divisor.

$\frac{121 x^{3}}{4}$

$\frac{121 x^{2}}{12}$

$12 x^{2}$

$4 x$

$0$

$363 x^{5}$

$0 x^{4}$

$0 x^{3}$

$0 x^{2}$

$0 x$

$0$

$363 x^{5}$

$121 x^{4}$

$0$

$121 x^{4}$

$0$

$0 x^{2}$

$0 x$

$121 x^{4}$

$\frac{121 x^{3}}{3}$

$0$

Step 11

The expression needs to be subtracted from the dividend, so change all the signs in $- 121 x^{4} - \frac{121 x^{3}}{3} + 0$

$\frac{121 x^{3}}{4}$

$\frac{121 x^{2}}{12}$

$12 x^{2}$

$4 x$

$0$

$363 x^{5}$

$0 x^{4}$

$0 x^{3}$

$0 x^{2}$

$0 x$

$0$

$363 x^{5}$

$121 x^{4}$

$0$

$121 x^{4}$

$0$

$0 x^{2}$

$0 x$

$121 x^{4}$

$\frac{121 x^{3}}{3}$

$0$

Step 12

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$\frac{121 x^{3}}{4}$

$\frac{121 x^{2}}{12}$

$12 x^{2}$

$4 x$

$0$

$363 x^{5}$

$0 x^{4}$

$0 x^{3}$

$0 x^{2}$

$0 x$

$0$

$363 x^{5}$

$121 x^{4}$

$0$

$121 x^{4}$

$0$

$0 x^{2}$

$0 x$

$121 x^{4}$

$\frac{121 x^{3}}{3}$

$0$

$\frac{121 x^{3}}{3}$

$0$

Step 13

Pull the next term from the original dividend down into the current dividend.

$\frac{121 x^{3}}{4}$

$\frac{121 x^{2}}{12}$

$12 x^{2}$

$4 x$

$0$

$363 x^{5}$

$0 x^{4}$

$0 x^{3}$

$0 x^{2}$

$0 x$

$0$

$363 x^{5}$

$121 x^{4}$

$0$

$121 x^{4}$

$0$

$0 x^{2}$

$0 x$

$121 x^{4}$

$\frac{121 x^{3}}{3}$

$0$

$\frac{121 x^{3}}{3}$

$0$

$0 x$

$0$

Step 14

Divide the highest order term in the dividend $\frac{121 x^{3}}{3}$ by the highest order term in divisor $12 x^{2}$ .

$\frac{121 x^{3}}{4}$

$\frac{121 x^{2}}{12}$

$\frac{121 x}{36}$

$12 x^{2}$

$4 x$

$0$

$363 x^{5}$

$0 x^{4}$

$0 x^{3}$

$0 x^{2}$

$0 x$

$0$

$363 x^{5}$

$121 x^{4}$

$0$

$121 x^{4}$

$0$

$0 x^{2}$

$0 x$

$121 x^{4}$

$\frac{121 x^{3}}{3}$

$0$

$\frac{121 x^{3}}{3}$

$0$

$0 x$

$0$

Step 15

Multiply the new quotient term by the divisor.

$\frac{121 x^{3}}{4}$

$\frac{121 x^{2}}{12}$

$\frac{121 x}{36}$

$12 x^{2}$

$4 x$

$0$

$363 x^{5}$

$0 x^{4}$

$0 x^{3}$

$0 x^{2}$

$0 x$

$0$

$363 x^{5}$

$121 x^{4}$

$0$

$121 x^{4}$

$0$

$0 x^{2}$

$0 x$

$121 x^{4}$

$\frac{121 x^{3}}{3}$

$0$

$\frac{121 x^{3}}{3}$

$0$

$0 x$

$0$

$\frac{121 x^{3}}{3}$

$\frac{121 x^{2}}{9}$

$0$

Step 16

The expression needs to be subtracted from the dividend, so change all the signs in $\frac{121 x^{3}}{3} + \frac{121 x^{2}}{9} + 0$

$\frac{121 x^{3}}{4}$

$\frac{121 x^{2}}{12}$

$\frac{121 x}{36}$

$12 x^{2}$

$4 x$

$0$

$363 x^{5}$

$0 x^{4}$

$0 x^{3}$

$0 x^{2}$

$0 x$

$0$

$363 x^{5}$

$121 x^{4}$

$0$

$121 x^{4}$

$0$

$0 x^{2}$

$0 x$

$121 x^{4}$

$\frac{121 x^{3}}{3}$

$0$

$\frac{121 x^{3}}{3}$

$0$

$0 x$

$0$

$\frac{121 x^{3}}{3}$

$\frac{121 x^{2}}{9}$

$0$

Step 17

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$\frac{121 x^{3}}{4}$

$\frac{121 x^{2}}{12}$

$\frac{121 x}{36}$

$12 x^{2}$

$4 x$

$0$

$363 x^{5}$

$0 x^{4}$

$0 x^{3}$

$0 x^{2}$

$0 x$

$0$

$363 x^{5}$

$121 x^{4}$

$0$

$121 x^{4}$

$0$

$0 x^{2}$

$0 x$

$121 x^{4}$

$\frac{121 x^{3}}{3}$

$0$

$\frac{121 x^{3}}{3}$

$0$

$0 x$

$0$

$\frac{121 x^{3}}{3}$

$\frac{121 x^{2}}{9}$

$0$

$\frac{121 x^{2}}{9}$

$0$

Step 18

Pull the next term from the original dividend down into the current dividend.

$\frac{121 x^{3}}{4}$

$\frac{121 x^{2}}{12}$

$\frac{121 x}{36}$

$12 x^{2}$

$4 x$

$0$

$363 x^{5}$

$0 x^{4}$

$0 x^{3}$

$0 x^{2}$

$0 x$

$0$

$363 x^{5}$

$121 x^{4}$

$0$

$121 x^{4}$

$0$

$0 x^{2}$

$0 x$

$121 x^{4}$

$\frac{121 x^{3}}{3}$

$0$

$\frac{121 x^{3}}{3}$

$0$

$0 x$

$0$

$\frac{121 x^{3}}{3}$

$\frac{121 x^{2}}{9}$

$0$

$\frac{121 x^{2}}{9}$

$0$

Step 19

Divide the highest order term in the dividend $- \frac{121 x^{2}}{9}$ by the highest order term in divisor $12 x^{2}$ .

$\frac{121 x^{3}}{4}$

$\frac{121 x^{2}}{12}$

$\frac{121 x}{36}$

$\frac{121}{108}$

$12 x^{2}$

$4 x$

$0$

$363 x^{5}$

$0 x^{4}$

$0 x^{3}$

$0 x^{2}$

$0 x$

$0$

$363 x^{5}$

$121 x^{4}$

$0$

$121 x^{4}$

$0$

$0 x^{2}$

$0 x$

$121 x^{4}$

$\frac{121 x^{3}}{3}$

$0$

$\frac{121 x^{3}}{3}$

$0$

$0 x$

$0$

$\frac{121 x^{3}}{3}$

$\frac{121 x^{2}}{9}$

$0$

$\frac{121 x^{2}}{9}$

$0$

Step 20

Multiply the new quotient term by the divisor.

$\frac{121 x^{3}}{4}$

$\frac{121 x^{2}}{12}$

$\frac{121 x}{36}$

$\frac{121}{108}$

$12 x^{2}$

$4 x$

$0$

$363 x^{5}$

$0 x^{4}$

$0 x^{3}$

$0 x^{2}$

$0 x$

$0$

$363 x^{5}$

$121 x^{4}$

$0$

$121 x^{4}$

$0$

$0 x^{2}$

$0 x$

$121 x^{4}$

$\frac{121 x^{3}}{3}$

$0$

$\frac{121 x^{3}}{3}$

$0$

$0 x$

$0$

$\frac{121 x^{3}}{3}$

$\frac{121 x^{2}}{9}$

$0$

$\frac{121 x^{2}}{9}$

$0$

$\frac{121 x^{2}}{9}$

$\frac{121 x}{27}$

$0$

Step 21

The expression needs to be subtracted from the dividend, so change all the signs in $- \frac{121 x^{2}}{9} - \frac{121 x}{27} + 0$

$\frac{121 x^{3}}{4}$

$\frac{121 x^{2}}{12}$

$\frac{121 x}{36}$

$\frac{121}{108}$

$12 x^{2}$

$4 x$

$0$

$363 x^{5}$

$0 x^{4}$

$0 x^{3}$

$0 x^{2}$

$0 x$

$0$

$363 x^{5}$

$121 x^{4}$

$0$

$121 x^{4}$

$0$

$0 x^{2}$

$0 x$

$121 x^{4}$

$\frac{121 x^{3}}{3}$

$0$

$\frac{121 x^{3}}{3}$

$0$

$0 x$

$0$

$\frac{121 x^{3}}{3}$

$\frac{121 x^{2}}{9}$

$0$

$\frac{121 x^{2}}{9}$

$0$

$\frac{121 x^{2}}{9}$

$\frac{121 x}{27}$

$0$

Step 22

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$\frac{121 x^{3}}{4}$

$\frac{121 x^{2}}{12}$

$\frac{121 x}{36}$

$\frac{121}{108}$

$12 x^{2}$

$4 x$

$0$

$363 x^{5}$

$0 x^{4}$

$0 x^{3}$

$0 x^{2}$

$0 x$

$0$

$363 x^{5}$

$121 x^{4}$

$0$

$121 x^{4}$

$0$

$0 x^{2}$

$0 x$

$121 x^{4}$

$\frac{121 x^{3}}{3}$

$0$

$\frac{121 x^{3}}{3}$

$0$

$0 x$

$0$

$\frac{121 x^{3}}{3}$

$\frac{121 x^{2}}{9}$

$0$

$\frac{121 x^{2}}{9}$

$0$

$\frac{121 x^{2}}{9}$

$\frac{121 x}{27}$

$0$

$\frac{121 x}{27}$

$0$

Step 23

The final answer is the quotient plus the remainder over the divisor.

$\frac{121 x^{3}}{4} - \frac{121 x^{2}}{12} + \frac{121 x}{36} - \frac{121}{108} + \frac{121 x}{27 (12 x^{2} + 4 x)}$