Pre-Algebra Examples

$g (- 6) = {(- 6)}^{2} + 2$

Step 1

Divide each term in $g (- 6) = {(- 6)}^{2} + 2$ by $- 6$ .

$\frac{g \cdot - 6}{- 6} = \frac{{(- 6)}^{2}}{- 6} + \frac{2}{- 6}$

Step 2

Simplify the left side.

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Step 2.1

Cancel the common factor of $- 6$ .

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Step 2.1.1

Cancel the common factor.

$\frac{g \cdot - 6}{- 6} = \frac{{(- 6)}^{2}}{- 6} + \frac{2}{- 6}$

Step 2.1.2

Divide $g$ by $1$ .

$g = \frac{{(- 6)}^{2}}{- 6} + \frac{2}{- 6}$

Step 3

Simplify the right side.

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Step 3.1

Combine the numerators over the common denominator.

$g = \frac{{(- 6)}^{2} + 2}{- 6}$

Step 3.2

Simplify the expression.

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Step 3.2.1

Raise $- 6$ to the power of $2$ .

$g = \frac{36 + 2}{- 6}$

Step 3.2.2

Add $36$ and $2$ .

$g = \frac{38}{- 6}$

Step 3.3

Cancel the common factor of $38$ and $- 6$ .

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Step 3.3.1

Factor $2$ out of $38$ .

$g = \frac{2 (19)}{- 6}$

Step 3.3.2

Cancel the common factors.

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Step 3.3.2.1

Factor $2$ out of $- 6$ .

$g = \frac{2 \cdot 19}{2 \cdot - 3}$

Step 3.3.2.2

Cancel the common factor.

$g = \frac{2 \cdot 19}{2 \cdot - 3}$

Step 3.3.2.3

Rewrite the expression.

$g = \frac{19}{- 3}$

Step 3.4

Move the negative in front of the fraction.

$g = - \frac{19}{3}$