Pre-Algebra Examples

$24 - 15 \div 3 \cdot - 9 + 14$

Step 1

Simplify each term.

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Step 1.1

Cancel the common factor of $3$ .

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Step 1.1.1

Move the leading negative in $- 15 \div 3$ into the numerator.

$24 + - 15 \div 3 \cdot - 9 + 14$

Step 1.1.2

Factor $3$ out of $- 9$ .

$24 + - 15 \div 3 \cdot (3 (- 3)) + 14$

Step 1.1.3

Cancel the common factor.

$24 + - 15 \div 3 \cdot (3 \cdot - 3) + 14$

Step 1.1.4

Rewrite the expression.

$24 - 15 \cdot - 3 + 14$

Step 1.2

Multiply $- 15$ by $- 3$ .

$24 + 45 + 14$

Step 2

Simplify by adding numbers.

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Step 2.1

Add $24$ and $45$ .

$69 + 14$

Step 2.2

Add $69$ and $14$ .

$83$