Finite Math Examples

$21 (11) + 10 y = 770$ , $7 (11) + 10 y = 840$

Step 1

Solve for $y$ in $231 + 10 y = 770$ .

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Step 1.1

Move all terms not containing $y$ to the right side of the equation.

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Step 1.1.1

Subtract $231$ from both sides of the equation.

$10 y = 770 - 231$

$77 + 10 y = 840$

Step 1.1.2

Subtract $231$ from $770$ .

$10 y = 539$

$77 + 10 y = 840$

$10 y = 539$

$77 + 10 y = 840$

Step 1.2

Divide each term in $10 y = 539$ by $10$ and simplify.

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Step 1.2.1

Divide each term in $10 y = 539$ by $10$ .

$\frac{10 y}{10} = \frac{539}{10}$

$77 + 10 y = 840$

Step 1.2.2

Simplify the left side.

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Step 1.2.2.1

Cancel the common factor of $10$ .

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Step 1.2.2.1.1

Cancel the common factor.

$\frac{10 y}{10} = \frac{539}{10}$

$77 + 10 y = 840$

Step 1.2.2.1.2

Divide $y$ by $1$ .

$y = \frac{539}{10}$

$77 + 10 y = 840$

$y = \frac{539}{10}$

$77 + 10 y = 840$

$y = \frac{539}{10}$

$77 + 10 y = 840$

$y = \frac{539}{10}$

$77 + 10 y = 840$

$y = \frac{539}{10}$

$77 + 10 y = 840$

Step 2

Replace all occurrences of $y$ with $\frac{539}{10}$ in each equation.

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Step 2.1

Replace all occurrences of $y$ in $77 + 10 y = 840$ with $\frac{539}{10}$ .

$77 + 10 (\frac{539}{10}) = 840$

$y = \frac{539}{10}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Simplify $77 + 10 (\frac{539}{10})$ .

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Step 2.2.1.1

Cancel the common factor of $10$ .

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Step 2.2.1.1.1

Cancel the common factor.

$77 + 10 (\frac{539}{10}) = 840$

$y = \frac{539}{10}$

Step 2.2.1.1.2

Rewrite the expression.

$77 + 539 = 840$

$y = \frac{539}{10}$

$77 + 539 = 840$

$y = \frac{539}{10}$

Step 2.2.1.2

Add $77$ and $539$ .

$616 = 840$

$y = \frac{539}{10}$

$616 = 840$

$y = \frac{539}{10}$

$616 = 840$

$y = \frac{539}{10}$

$616 = 840$

$y = \frac{539}{10}$

Step 3

Since $616 = 840$ is not true, there is no solution.

No solution

Step 4