Chemistry Examples

$N a C l$

Step 1

To find the mass of $1$ mole of $N a C l$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $N a C l$ $=$ $(mass of Na)$ + $(mass of Cl)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $N a C l$ $=$ $(22.98999977)$ + $(35.45000076)$

Step 3

Simplify the result.

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Step 3.1

Remove parentheses.

mass of $1$ mole of $N a C l = 22.98999977 + 35.45000076 g$

Step 3.2

Add $22.98999977$ and $35.45000076$ .

mass of $1$ mole of $N a C l = 58.44000053 g$

Step 4

One mole of any gas occupies $22.4 L$ at STP (standard temperature and pressure).

$V = 22.4 L$

Step 5

Density is mass over volume.

$\frac{58.44000053 g}{22.4 L}$

Step 6

Factor $58.44000053$ out of $58.44000053 g$ .

$\frac{58.44000053 (g)}{22.4 L}$

Step 7

Factor $22.4$ out of $22.4 L$ .

$\frac{58.44000053 (g)}{22.4 (L)}$

Step 8

Separate fractions.

$\frac{58.44000053}{22.4} \cdot \frac{g}{L}$

Step 9

Divide $58.44000053$ by $22.4$ .

$2.60892859 \frac{g}{L}$

Step 10

Combine $2.60892859$ and $\frac{g}{L}$ .

$\frac{2.60892859 g}{L}$