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Solve for g (95gal)/1(min)=(ft^3)/s

$\frac{95 gal}{1} (\min) = \frac{f t^{3}}{s}$

Step 1

Combine fractions.

$95 gal \min = \frac{f t^{3}}{s}$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$

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