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Solve for d d-3=-3

$d - 3 = - 3$

Step 1

Add $3$ to both sides of the equation.

$d = - 3 + 3$

Step 2

Add $- 3$ and $3$ .

$d = 0$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$

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