Algebra Examples

$\frac{y - 6}{- 5} = \frac{- 2}{y - 9}$

Step 1

Simplify both sides.

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Step 1.1

Move the negative in front of the fraction.

$- \frac{y - 6}{5} = \frac{- 2}{y - 9}$

Step 1.2

Move the negative in front of the fraction.

$- \frac{y - 6}{5} = - \frac{2}{y - 9}$

Step 2

Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.

$- (y - 6) (y - 9) = 5 \cdot - 2$

Step 3

Solve the equation for $y$ .

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Step 3.1

Divide each term in $- (y - 6) (y - 9) = 5 \cdot - 2$ by $- 1$ and simplify.

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Step 3.1.1

Divide each term in $- (y - 6) (y - 9) = 5 \cdot - 2$ by $- 1$ .

$\frac{- (y - 6) (y - 9)}{- 1} = \frac{5 \cdot - 2}{- 1}$

Step 3.1.2

Simplify the left side.

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Step 3.1.2.1

Reduce the expression by cancelling the common factors.

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Step 3.1.2.1.1

Dividing two negative values results in a positive value.

$\frac{(y - 6) (y - 9)}{1} = \frac{5 \cdot - 2}{- 1}$

Step 3.1.2.1.2

Divide $(y - 6) (y - 9)$ by $1$ .

$(y - 6) (y - 9) = \frac{5 \cdot - 2}{- 1}$

Step 3.1.2.2

Expand $(y - 6) (y - 9)$ using the FOIL Method.

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Step 3.1.2.2.1

Apply the distributive property.

$y (y - 9) - 6 (y - 9) = \frac{5 \cdot - 2}{- 1}$

Step 3.1.2.2.2

Apply the distributive property.

$y \cdot y + y \cdot - 9 - 6 (y - 9) = \frac{5 \cdot - 2}{- 1}$

Step 3.1.2.2.3

Apply the distributive property.

$y \cdot y + y \cdot - 9 - 6 y - 6 \cdot - 9 = \frac{5 \cdot - 2}{- 1}$

Step 3.1.2.3

Simplify and combine like terms.

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Step 3.1.2.3.1

Simplify each term.

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Step 3.1.2.3.1.1

Multiply $y$ by $y$ .

$y^{2} + y \cdot - 9 - 6 y - 6 \cdot - 9 = \frac{5 \cdot - 2}{- 1}$

Step 3.1.2.3.1.2

Move $- 9$ to the left of $y$ .

$y^{2} - 9 \cdot y - 6 y - 6 \cdot - 9 = \frac{5 \cdot - 2}{- 1}$

Step 3.1.2.3.1.3

Multiply $- 6$ by $- 9$ .

$y^{2} - 9 y - 6 y + 54 = \frac{5 \cdot - 2}{- 1}$

Step 3.1.2.3.2

Subtract $6 y$ from $- 9 y$ .

$y^{2} - 15 y + 54 = \frac{5 \cdot - 2}{- 1}$

Step 3.1.3

Simplify the right side.

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Step 3.1.3.1

Move the negative one from the denominator of $\frac{5 \cdot - 2}{- 1}$ .

$y^{2} - 15 y + 54 = - 1 \cdot (5 \cdot - 2)$

Step 3.1.3.2

Rewrite $- 1 \cdot (5 \cdot - 2)$ as $- (5 \cdot - 2)$ .

$y^{2} - 15 y + 54 = - (5 \cdot - 2)$

Step 3.1.3.3

Multiply $- (5 \cdot - 2)$ .

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Step 3.1.3.3.1

Multiply $5$ by $- 2$ .

$y^{2} - 15 y + 54 = - - 10$

Step 3.1.3.3.2

Multiply $- 1$ by $- 10$ .

$y^{2} - 15 y + 54 = 10$

Step 3.2

Subtract $10$ from both sides of the equation.

$y^{2} - 15 y + 54 - 10 = 0$

Step 3.3

Subtract $10$ from $54$ .

$y^{2} - 15 y + 44 = 0$

Step 3.4

Factor $y^{2} - 15 y + 44$ using the AC method.

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Step 3.4.1

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $44$ and whose sum is $- 15$ .

$- 11, - 4$

Step 3.4.2

Write the factored form using these integers.

$(y - 11) (y - 4) = 0$

Step 3.5

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$y - 11 = 0$

$y - 4 = 0$

Step 3.6

Set $y - 11$ equal to $0$ and solve for $y$ .

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Step 3.6.1

Set $y - 11$ equal to $0$ .

$y - 11 = 0$

Step 3.6.2

Add $11$ to both sides of the equation.

$y = 11$

Step 3.7

Set $y - 4$ equal to $0$ and solve for $y$ .

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Step 3.7.1

Set $y - 4$ equal to $0$ .

$y - 4 = 0$

Step 3.7.2

Add $4$ to both sides of the equation.

$y = 4$

Step 3.8

The final solution is all the values that make $(y - 11) (y - 4) = 0$ true.

$y = 11, 4$