Algebra Examples

$2 π r h + 2 π r^{2}$ ; $r = 2.5$ , $h = 16$

Step 1

Replace the variable $r$ with $2.5$ in the expression.

$2 π (2.5) \cdot h + 2 π {(2.5)}^{2}$

Step 2

Replace the variable $h$ with $16$ in the expression.

$2 π (2.5) \cdot (16) + 2 π {(2.5)}^{2}$

Step 3

Simplify each term.

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Step 3.1

Multiply $2 π (2.5)$ .

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Step 3.1.1

Multiply $2.5$ by $2$ .

$5 π \cdot 16 + 2 π {(2.5)}^{2}$

Step 3.1.2

Multiply $5$ by $π$ .

$15.70796326 \cdot 16 + 2 π {(2.5)}^{2}$

Step 3.2

Multiply $15.70796326$ by $16$ .

$251.32741228 + 2 π {(2.5)}^{2}$

Step 3.3

Raise $2.5$ to the power of $2$ .

$251.32741228 + 2 π \cdot 6.25$

Step 3.4

Multiply $2 π \cdot 6.25$ .

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Step 3.4.1

Multiply $6.25$ by $2$ .

$251.32741228 + 12.5 π$

Step 3.4.2

Multiply $12.5$ by $π$ .

$251.32741228 + 39.26990816$

Step 4

Add $251.32741228$ and $39.26990816$ .

$290.59732045$