Algebra Examples

$t_{n} = n (6 n - 2)$

Step 1

Substitute in the value of $n$ to find the $n$ th term.

$t_{2} = (2) (6 (2) - 2)$

Step 2

Multiply $6$ by $2$ .

$t_{2} = 2 (12 - 2)$

Step 3

Subtract $2$ from $12$ .

$t_{2} = 2 \cdot 10$

Step 4

Multiply $2$ by $10$ .

$t_{2} = 20$