Algebra Examples

$\sqrt{6 - 15 \cdot - 2} = 5 (- 2) + d$

Step 1

Rewrite the equation as $5 (- 2) + d = \sqrt{6 - 15 \cdot - 2}$ .

$5 (- 2) + d = \sqrt{6 - 15 \cdot - 2}$

Step 2

Multiply $5$ by $- 2$ .

$- 10 + d = \sqrt{6 - 15 \cdot - 2}$

Step 3

Simplify $\sqrt{6 - 15 \cdot - 2}$ .

Tap for more steps...

Step 3.1

Multiply $- 15$ by $- 2$ .

$- 10 + d = \sqrt{6 + 30}$

Step 3.2

Add $6$ and $30$ .

$- 10 + d = \sqrt{36}$

Step 3.3

Rewrite $36$ as $6^{2}$ .

$- 10 + d = \sqrt{6^{2}}$

Step 3.4

Pull terms out from under the radical, assuming positive real numbers.

$- 10 + d = 6$

Step 4

Move all terms not containing $d$ to the right side of the equation.

Tap for more steps...

Step 4.1

Add $10$ to both sides of the equation.

$d = 6 + 10$

Step 4.2

Add $6$ and $10$ .

$d = 16$