Algebra Examples

Find Where Undefined/Discontinuous 15/(a^2-1)=5/(2a-2)
Step 1
Subtract from both sides of the equation.
Step 2
Simplify each term.
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Step 2.1
Simplify the denominator.
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Step 2.1.1
Rewrite as .
Step 2.1.2
Since both terms are perfect squares, factor using the difference of squares formula, where and .
Step 2.2
Factor out of .
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Step 2.2.1
Factor out of .
Step 2.2.2
Factor out of .
Step 2.2.3
Factor out of .
Step 3
Set the denominator in equal to to find where the expression is undefined.
Step 4
Solve for .
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Step 4.1
If any individual factor on the left side of the equation is equal to , the entire expression will be equal to .
Step 4.2
Set equal to and solve for .
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Step 4.2.1
Set equal to .
Step 4.2.2
Subtract from both sides of the equation.
Step 4.3
Set equal to and solve for .
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Step 4.3.1
Set equal to .
Step 4.3.2
Add to both sides of the equation.
Step 4.4
The final solution is all the values that make true.
Step 5
Set the denominator in equal to to find where the expression is undefined.
Step 6
Solve for .
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Step 6.1
Divide each term in by and simplify.
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Step 6.1.1
Divide each term in by .
Step 6.1.2
Simplify the left side.
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Step 6.1.2.1
Cancel the common factor of .
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Step 6.1.2.1.1
Cancel the common factor.
Step 6.1.2.1.2
Divide by .
Step 6.1.3
Simplify the right side.
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Step 6.1.3.1
Divide by .
Step 6.2
Add to both sides of the equation.
Step 7
The equation is undefined where the denominator equals , the argument of a square root is less than , or the argument of a logarithm is less than or equal to .
Step 8