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Convert from Interval to Inequality (1,6]

$(1, 6]$

Step 1

The inequality form is $1 < x \leq 6$ .

$1 < x \leq 6$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$

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